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3 years ago

A substance that contains only one kind of matter is known as a (n)

Physics

1 answer:

8090 [49]3 years ago

5 0

I think the question is fishing for "element".

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Anna71 [15]

Answer:

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3 years ago

What is the speed of a wave if the wavelength is 200 m and the period is 20 s?

goblinko [34]

Here is your answer

We know that

Velocity = Wavelength/Time period

Here,

Wavelength = 200m

Time period= 20 secs

So,

Velocity= 200/20 m/s

v= 10m/s

HOPE IT IS USEFUL

6 0

3 years ago

The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reacti

mestny [16]

Answer:

500n

Explanation:

7 0

3 years ago

Read 2 more answers

If the mass of a pendulum is increased (with other factors controller), would the period (time) decrease or stay the same?

Akimi4 [234]

The period of the pendulum depends only on the length from the pivot to the "center of mass". So if the string has no mass, then the amount of mass on the end doesn't make any difference.
But if the pendulum is suspended on, say, a chain with mass, then the more mass on the bottom, the lower the center of mass is, and the longer the period is.

8 0

4 years ago

A 75-hp (shaft output) motor that has an efficiency of 91.0 percent is worn out and is to be replaced by a high- efficiency moto

daser333 [38]

Convert the shaft ouput from HP to kW

Shaft output = 75HP = 55.93kW

1st: Finding for the power consumption based on 55.93kW output

Power consumption (Old) = 55.93kW / .910 = 61.46kW

Power consumption (New) = 55.93kW / .954 = 58.63kW

2nd: Total power used in kWh:

Power Used = Power consumption * load factor * Hours:

Power (Old) = 61.46kW * .75 * 4368 = 201343 kWh

Power (New) = 58.63kW * .75 * 4368 = 192072 kWh

Energy saved = 201343 kWh - 192072 kWh = 9,271 kWh

3rd: Calculating for the price:

Price = kW-Hr * $/kWh

Price (Old) = 201343kWh * $0.08/kWh = $16107.44

Price (New) = 192072 kWh * $0.08/kWh = $15365.76

Cost saved = $16107.44 - $15365.76 = $741.68/yr

4th: Setting up the cost equation:

Cost over time, F(t) = Motor_Cost + (Price * Number of Years, t)

Cost (Old) = 5449 + 16107.44*t

Cost (New) = 5520 + 15365.76*t

Equate the two to find for t when they cost equally:

5449 + 16107.44*t = 5520 + 15365.76*t

16107.44*t = 15365.76*t +71

16107.44*t - 15365.76*t = 71

741.68*t = 71

t = 71 / 741.68 = .095 years = 35 days

So the payback period is after 35 days.

6 0

3 years ago