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morpeh [17]
3 years ago
6

The achievement of lifting a rocket off the ground and into space can be explained by

Physics
1 answer:
lawyer [7]3 years ago
4 0

Answer:

The achievement of lifting a rocket off the ground and into space can be explained by Newton's third law of motion. What is required for a rocket to lift off into space? Thrust is required for a rocket to lift off into space, ... An object that travels around another object in space is called a satellite.

Explanation:

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Which of the following is an example of a chemical property? Density Solubility Flammability Magnetism
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The answer should be flammability
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Wha is the frequency of a wave having a period equal to 18 seconds?
Rainbow [258]

Answer:

5.5 × 10-2 hertz

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

= 0.055 per second          (1 cycle per second = 1 Hertz)

Thus, we can conclude that the frequency of the wave is 5.5 X 10^{-2} hertz.

Hopes this helps, love <3

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3 years ago
A is a non-contact breaking of the basketball rules <br>​
ElenaW [278]
A foul occurs when a player or coach breaks a rule covering either contact with an opposing player of unsportsmanlike action. Basketball is a so-called non-contact sport but basketball rules recognize that is not really possible to have 10 players running around a small area without making some contact.
7 0
3 years ago
Consider a 30-cm-diameter hemispherical enclosure. The dome is maintained at 600 K, and heat is supplied from the dome at a rate
SIZIF [17.4K]

Answer:

\epsilon_2=0.098

Explanation:

Diameter d=30cm=0.3m

Temperature T=600k

Rate of supply r=65W

Emissivity of base surface \in_b =0.55

Temperature at base T_b=400k

Generally the equation for Area of base surface is mathematically given by

 A_b=\frac{\pi}{4}d^2

 A_b=\frac{\pi}{4}0.3^2

 A_b=0.0707m^2

Generally the equation for Area of Hemispherical dome is mathematically given by

 A_h=\frac{\pi}{2}d^2

 A_h=\frac{\pi}{2}0.3^2

 A_h=0.1414m^2

Since base is a flat surface

 F_{11}+F_{12}=1

 F_{11}=0

Therefore

 F_{12}=1

 A_b=0.0707m^2

Generally the equation for Net rate of radiation heat transfer between two surfaces is mathematically given by

 Q_{21}=-Q_{12}

 Q_{21}=\frac{\sigma(T_1^4-T_2^4)}{\frac{1-\epsilon}{A_b\epsilon_1} +\frac{1}{A_bF_{12}} +\frac{1-\epsilon_2}{A_h*\epsilon_2} }

Where

 \sigma=5.67*10^{-8}

Therefore

  65=\frac{(5.67*10^{-8}(400^4-600^4))}{\frac{1-0.55}{0.0707*0.55}+\frac{1}{0.0707}+\frac{1-\epsilon_2}{0.1414*\epsilon_2}}

 \epsilon_2=0.098

 \epsilon_2 \approx 0.1

Therefore  the emissivity of the dome is

 \epsilon_2=0.098

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3 years ago
What happens to the piece of steel?
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The answer should be c....
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