You notice that heat is released during a chemical reaction. This reaction is a(n) _______ reaction. endothermic heat hot exothe
1 answer:
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A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, , backward
The frictional force can be written as
where
is the coefficient of kinetic friction
is the mass of the motorbike
is the acceleration of gravity
Therefore the net force is given by
And substituting, we find
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
where
m is the mass
a is the acceleration
In this problem, we have
is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
s = 350 m
Solving for v,
4)
For this part of the problem, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
Solving for t, we find
Learn more about Newton's laws of motion and accelerated motion:
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Answer:
man upward acceleration is 0.14m/s^2
Explanation:
given data:
mass of man = 72 kg
downward force = 360 N
The mass of man of weight 72 kg is hang from two sections of rope, one section pf rope ties around man waist and other section is ties in man hands. when he pulls down the rope with 360 N force then each section of rope pulls with 360 N
we know that
Weight= mass × gravity= 72kg × 9.8 = 705.6N
Force = mass× acceleration
Force= -705.6 + (2 × 358) = 10.4 N