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aliya0001 [1]
3 years ago
11

You notice that heat is released during a chemical reaction. This reaction is a(n) _______ reaction. endothermic heat hot exothe

rmic
Physics
1 answer:
lidiya [134]3 years ago
8 0
The reaction is an exothermic reaction.
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What type of image is formed by a lens if m = -2.0?
natka813 [3]
The best answer seems to be the C) <span>A virtual image that is smaller than the object. Because when m is smaller than 1, then the image is virtual. But I'm not 100% sure.</span>
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3 years ago
Expand (2x + y) (2x - y).​
KiRa [710]

Answer: 4x²-y²

Explanation:

FORMULA

a²-b²=(a+b)(a-b)

-----------------------------

(a+b)(a-b)=a²-b²

(2x+y)(2x-y)=(2x)²-(y)²

                  =4x²-y²

Hope this helps!! :)

Please let me know if you have any question

8 0
3 years ago
A 4400 W motor is used to do work. If the motor is used for 200 s, how much work could it do? (Power: P = W/t)
Inga [223]
Hope this helps, have a great day ahead!

7 0
3 years ago
Read 2 more answers
A runner runs 300 m at an average speed of 3.0 m/s. She then runs another 300m at an average
Kaylis [27]

Answer:

B. 4 m/s

Explanation:

v=d/t

Running for 300 m at 3 m/s takes 100 seconds and running at 300 m at 6 m/s takes 50 seconds. 100 s + 50 s = 150 s (total time). Total distance is 600 m, so 600 m/ 150 s = 4 m/s.

3 0
4 years ago
Pleaseeeee help me with b, c, and d. There are no angles.
taurus [48]

Answer:

a. 150 J

b. 150 J

c. 0 J

d. 0 J

Explanation:

The given parameters are;

The horizontal force with which the man pulls the canister, F = 50 N

The distance he moves the vacuum cleaner, d = 3.0 m

a. Work done, W = Force applied, F × Distance moved by the force, d

Therefore, for the work done by the 50 N force on the canister, we have;

W = 50 N × 3.0 m = 150 N·m = 150 J

b. Given that he pulls the canister at a constant speed, we have;

The acceleration of the canister, a = 0 m/s²

Therefore, the net force on the canister, F_{NET} = F - F_{Friction}  = m × a

Where;

m = The mass of the canister

a = The acceleration of the canister

F = The applied force = 50 N

F_{Friction} = The force of friction

∴ F_{NET} = m × a = m × 0 m/s² = 0 N

Therefore;

F_{NET} =  F - F_{Friction} = 0 N

From which we have;

F = F_{Friction} = 50 N (The applied force, F is equal to the force of friction,

The work done by friction = The force of friction × The distance in which the force of friction acts

∴ The work done by friction = F_{Friction} × d - 50 N × 3.0 m = 150 J

The work done by friction = 150 J

c. The normal force, N acts perpendicular to the force of friction

The distance the canister moves in the perpendicular direction, d_p = 0 m

∴ The work done by the normal direction = N × d_p = N × 0 m = 0 J

The work done by the normal direction = 0 J

d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N

Therefore, the weight, W, acts perpendicular to the line of motion of canister

The distance the canister moves in the direction of the weight, d_{wieght} = 0 m

Therefore, the work done by the weight = W × d_{wieght} = W × 0 m = 0 J

The work done by the weight = 0 J

7 0
3 years ago
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