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3 years ago

No links or spam i will report! please help thank you!<3

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

A. The two lines are neither parallel nor perpendicular.

Step-by-step explanation:

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HEYOO PEEPS Find the scale factor.

valentina_108 [34]

Answer:

I think it is 9

Step-by-step explanation:

as for number one I did 5×7=35 overall and 15×21= 315

then I did 315÷35=9 which is the scale factor.

hope this is correct and help u understand:)

7 0

3 years ago

Read 2 more answers

A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18π meters.

Whitepunk [10]

Answer:

$A=81\pi\ m^{2}$

Step-by-step explanation:

Step 1

Find the radius of the circular cross section

we know that

The circumference is equal to

$C=2\pi r$

we have

$C=18\pi\ m$

substitute and solve for r

$18\pi=2\pi r$

simplify

$18=2 r$

$r=9\ m$

Step 2

Find the area of the circular cross section

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=9\ m$

substitute

$A=\pi (9)^{2}$

$A=81\pi\ m^{2}$

8 0

3 years ago

XLiV represents 64 true ya false

V125BC [204]

Answer:

False

Step-by-step explanation:

Given

$XLIV = 64$

Required

True or False

The above numeral can be split as follows:

$XLIV = XL + IV$

X means 10 and L means 50.

But because X (10) which is smaller comes before L (50), XL is executed as:

$XL = -10 + 50$

$XL = 40$

In Roman numerals;

$IV = 4$

Substitute 40 for XL and 4 for IV.

$XLIV = 40 + 4$

$XLIV = 44$

Hence;

<em /> $XLIV = 64$ <em> is false</em>

7 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago

F(x) = 4x^2+5x-12 evaluate f(-3)

Natali5045456 [20]

F(-3)=4(-3)^2+5(-3)-12
=36-15-12
=36-27
=-9

4 0

3 years ago