Answer:
![\boxed{ \rm \: Volume_{(Cylinder)} \approx \: 461.6 \: {m}^{3} } \rm (rounded \: to \: nearest \: tenth)](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%5Capprox%20%5C%3A%20461.6%20%20%5C%3A%20%20%7Bm%7D%5E%7B3%7D%20%7D%20%5Crm%20%28rounded%20%5C%3A%20to%20%5C%3A%20nearest%20%5C%3A%20tenth%29)
Step-by-step explanation:
Given dimensions:
- Radius of the cylinder = 7 metres
- Height of the cylinder = 3 metres
Given value of π :
To find:
- The Volume of the cylinder
Solution:
Here, we'll need to use the formulae of the volume of cylinder,to find it's volume.Its actually like a savior while solving these type of questions.
![\pink{\star}\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}\pink{\star}](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cstar%7D%5Cboxed%7B%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%7Br%7D%20%7B%7D%5E%7B2%7D%20h%7D%5Cpink%7B%5Cstar%7D)
where,
- π = 3.14
- r² = (radius)²
- h = height
Plug/substitute them onto the formulae,then simplify it using PEMDAS.
- [We'll substitute the value of π later]
![\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2} \times 3](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%287%29%20%7B%7D%5E%7B2%7D%20%20%5Ctimes%203)
![\rm \: Volume_{(Cylinder)} = \pi(49)(3)](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%2849%29%283%29)
![\rm \: Volume_{(Cylinder)} = 147\pi \:](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20147%5Cpi%20%5C%3A%20)
- Now substitute the value of π.
![\rm \: Volume_{(Cylinder)} = 147 \times 3.14](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20147%20%5Ctimes%203.14)
![\rm \: Volume_{(Cylinder)} = 461.58 \: {m}^{3}](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20461.58%20%5C%3A%20%20%7Bm%7D%5E%7B3%7D%20)
![\boxed{\rm \: Volume_{(Cylinder)} \approx \: 461.6 \: {m}^{3}} \rm (rounded \: to \: nearest \: tenth) \:](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%5Capprox%20%5C%3A%20461.6%20%20%5C%3A%20%20%7Bm%7D%5E%7B3%7D%7D%20%5Crm%20%28rounded%20%5C%3A%20to%20%5C%3A%20nearest%20%5C%3A%20tenth%29%20%5C%3A%20)
<u>Hence, we can conclude that:</u>
The volume of the cylinder is approximately
461.6 m³.
![\rule{225pt}{2pt}](https://tex.z-dn.net/?f=%20%5Crule%7B225pt%7D%7B2pt%7D)
Answer:
100%
Step-by-step explanation:
Trust me
2p = 396/63 (= 6.2857)
p = 198/63 (= 3.14)
Answer:
-1/2 is the work
Step-by-step explanation:
hope this helped