Step-by-step explanation:
The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables and c is the constant term. The other different forms to find and represent the equation of a line are slope-intercept form, point-slope form, two-point form, intercept form, and normal form.
Answer:
V = 19.625h
Step-by-step explanation:
Volume of a cylinder V = πr²h
r is the radius
h is the height
Given
r = base/2
r= 5/2
r= 2.5
Substitute into the formula
V = π(2.5)²h
V = 3.14*6.25h
V = 19.625h
hence the required expression is V = 19.625h
39 meters in 3 minutes means 13 meters each minute and 26 meters in two minutes. Multiply by 1,000 to convert it into 26000 millimeters.
Using the dot plot and statistical concepts, it is found that the correct option is:
- Their means will be most affected because this value will be an outlier.
<h3>What is a dot plot?</h3>
- The dot plot shows the <u>number of times each measure appears in the data-set.</u>
In this problem, for both Walter and Janine, the dot plots are cluster between 80 and 90, which means that their grades are in this range.
- Hence, for both, a grade of 65 would be an outlier, and the measure that is most affected by outliers is the mean.
Hence, the correct option is:
- Their means will be most affected because this value will be an outlier.
You can learn more about dot plot at brainly.com/question/24912483
<span>These are points where f ' = 0. Use the quiotent rule to find f '.
f ' (x) = [(x^3+2)(1) - (x)(3x^2)] / (x^3+2)^2
f ' (x) = (2 - 2x^3) / (x^3 + 2)^2
Set f ' (x) = 0 and solve for x.
f ' (x) = 0 = (2-2x^3) / (x^3+2)^2
Multiply both sides by (x^3+2)^2
(x^3+2)^2 * 0 = (x^3+2)^2 * [(2-2x^3)/(x^3+2)^2]
0 = 2 - 2x^3
Add 2x^3 to both sides
2x^3 + 0 = 2x^3 + 2 - 2x^3
2x^3 = 2
Divide both sides by 2
2x^3 / 2 = 2 / 2
x^3 = 1
Take cube roots of both sides
cube root (x^3) = cube root (1)
x = 1. This is our critical point
2) Points where f ' does not exist.
We know f ' (x) = (2-2x^3) / (x^3+2)^2
You cannot divide by 0 ever so f ' does not exist where the denominator equals 0
(x^3 + 2)^2 = 0. Take square roots of both sides
sqrt((x^3+2)^2) = sqrt(0)
x^3 + 2 = 0. Add -2 to both sides.
-2 + x^3 + 2 = -2 + 0
x^3 = -2. Take cube roots of both sides.
cube root (x^3) = cube root (-2)
x = cube root (-2). This is where f ' doesnt exist. However, it is not in our interval [0,2]. Thus, we can ignore this point.
3) End points of the domain.
The domain was clearly stated as [0, 2]. The end points are 0 and 2.
Therefore, our only options are: 0, 1, 2.
Check the intervals
[0, 1] and [1, 2]. Pick an x value in each interval and determine its sign.
In [0, 1]. Check 1/2. f ' (1/2) = (7/4) / (17/8)^2 which is positive.
In [1, 2]. Check 3/2. f ' (3/2) = (-19/4) / (43/8)^2 which is negative.
Therefore, f is increasing on [0, 1] and decreasing on [1, 2] and 1 is a local maximum.
f (0) = 0
f (1) = 1/3
f (2) = 1/5
Therefore, 0 is a local and absoulte minimum. 1 is a local and absolute
maximum. Finally, 2 is a local minimum. </span><span>Thunderclan89</span>
