Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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I think that is the mean or the mode . I think more on mean
Answer:
B
Step-by-step explanation:
use quadratic formula: (-b ±√b²-4ac) ÷ 2a
a = 10, b = -9, c = -6
The vertex form:

The axis of symetry is x = h.

We have

Substitute:

<h3>Answer: x = 3</h3>
X^2 +x -12 = 0
<span>Factor : ( x -3 )*( x +4 )</span>