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3 years ago

30 points!

1 answer:

6 0

To divide scientific notation, divide the decimals and subtract the powers of 10 for a result of 8.6/3.2=2.6875 multiplied by ten to the 8-3=5. B is the correct answer.

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Solve for m <br> 0.2m=3.5

fredd [130]

Answer:

m = 17.5

Step-by-step explanation:

Given 0.2m=3.5, we want to solve for m. This involves isolating m on the left side. To accomplish this, divide both sides by 0.2, obtaining:

m = 3.5/0.2, or m = 17.5

7 0

3 years ago

Each week, heather's company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

Pepsi [2]

Answer:

Step-by-step explanation:

Step one:

Given data for Heather's company

Fixed cost = $5000

Additional cost = $250

in a week there are 168 hours

hence they will produce a total of 168/5= 33.6

=34 systems

the expression for the total cost can be modeled as

c=mn+f

where c=total cost

m= the Additional cost

n= number of systems produced per hour

h= the number of systems produced per hour

f= fixed cost

Step two:

c=mn+f

given that n=34, we can find the total cost as

c=250(34)+5000

c=8500+5000

c=13500

the total cost for each week is $13,500

3 0

3 years ago

Helppp plsss. i have to turn this in asap

Lady bird [3.3K]

Answer:

y= 2x-5

Step-by-step explanation:

The slope formula is m=(y2-y1)/(x2-x1)

-3-1 / 1-3 = -4/-2= 2=m

The Y interception- y=mx+b using coordinates (3,1)

1=2(3)+b

1=6+b (subtracting 6 on both sides to isolate b)

-5=b

plug it in

y=2x-5

6 0

2 years ago

Find the exact value of the trigonometric expression.

Dmitrij [34]

$\bf \textit{Half-Angle Identities}
\\\\
sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}}
\qquad 
cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}\\\\
-------------------------------\\\\
\cfrac{1}{12}\cdot 2\implies \cfrac{1}{6}\qquad therefore\qquad \cfrac{\pi }{12}\cdot 2\implies \cfrac{\pi }{6}~thus~ \cfrac{\quad \frac{\pi }{6}\quad }{2}\implies \cfrac{\pi }{12}$

$\bf sec\left( \frac{\pi }{12} \right)\implies sec\left( \cfrac{\frac{\pi }{6}}{2} \right)\implies \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\impliedby \textit{now, let's do the bottom}
\\\\\\
cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{1+cos\left( \frac{\pi }{6} \right)}{2}}\implies \pm\sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \pm\sqrt{\cfrac{\frac{2+\sqrt{3}}{2}}{2}}$

$\bf \pm \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \pm\cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\implies \pm \cfrac{\sqrt{2+\sqrt{3}}}{2}
\\\\\\
therefore\qquad \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\implies \cfrac{2}{\sqrt{2+\sqrt{3}}}$

which simplifies thus far to

$\bf \cfrac{2}{\sqrt{2+\sqrt{3}}}\cdot \cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\cdot \stackrel{conjugate}{\cfrac{2-\sqrt{3}}{2-\sqrt{3}}}
\\\\\\
\cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{2^2-(\sqrt{3})^2}\implies \cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{1}$

$\bf 2\sqrt{2+\sqrt{3}}(2-\sqrt{3})\impliedby \stackrel{\textit{keep in mind that}}{(2-\sqrt{3})=(\sqrt{2-\sqrt{3}})(\sqrt{2-\sqrt{3}})}
\\\\\\
2\sqrt{2+\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}
\\\\\\
2\sqrt{(2+\sqrt{3})(2-\sqrt{3})\cdot (2-\sqrt{3})}
\\\\\\
2\sqrt{[2^2-(\sqrt{3})^2]\cdot (2-\sqrt{3})}\implies 2\sqrt{1(2-\sqrt{3})}
\\\\\\
2\sqrt{2-\sqrt{3}}$

7 0

4 years ago

Please help! I really need help please I will give Brainliest!

Ostrovityanka [42]

Answer:

A) 4x+12y

B) 2(2x+6y) is one way to do it

Step-by-step explanation:

1+1+2 is 4 and 12y cannot be added to anything.

2 x 2 is 2 ans 6 x 2 is 12

4 0

3 years ago