Answer:
7.236
Step-by-step explanation:
(3x^5y)^2=
3^2=9
(x^5)^2=x^10
y^2=y^2
(3x^5y)^2=9x^10y^2
9x^10y^2(4x^3y^5)=
9*4=36
x^10*x^3=x^13
y^2*y^5=y^7
9x^19y^2(4x^3y^5)= 36x^13y^7
Final answer: 36x^13y^7
Since only the principal value, interest rate and interest period are given, we can deduce that "finance charge" only includes the interest to be paid at the end of the term. This can be obtained by subtracting the principal value from the future value which we will solve for.
The future value can be solved by using the following compound interest formula:
Let:
F = Future value
P = Principal value
r<span> = annual interest rate </span>
n<span> = number of times that interest is compounded per year</span>
t<span> = number of years</span>
F = P(1 + r/n)^nt
Substituting the given values:
F = 4250(1 + 0.1325/12)^(12*2)
F = 5531.54
Subtracting P from F:
Finance charge = 5531.54 - 4250 = 1281.54
Therefore the finance charge is $1,281.54
Answer:
- the value should be twns and ones
Step-by-step explanation:
1 8=tens 8(1 ones)
Answer:
11. AW║BY
12. DX║YZ
13. AW║YZ
14. AW║DZ
Step-by-step explanation:
11. If alternate interior angles are congruent, the lines the transversal crosses are parallel.
12. The sum ∠5+∠6 is an alternate interior angle with ∠10. The reasoning of problem 11 applies.
13. If same-side interior angles are suppplementary, the lines the transversal crosses are parallel.
14. Lines perpendicular to the same line are parallel.