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Lostsunrise [7]
3 years ago
14

PLZZZZZ HELP NEEDED ASAP WILL GIVE BRAINLIEST (IF RIGHT)

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0

x= 90° - 63° = 27° (NO perpendicular to AOB)

angle DOB = (90°+90°) -128° (angles on a straight line)

= 180° - 128°

= 52°

y= 180° - x - 63° - angle DOB (angles on a straight line)

=180° - 27° - 63° - 52°

= 38°

I'm not sure of the answer tho^^ good luck!

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Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

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The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

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