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Kruka [31]
3 years ago
11

a sales person works 3 days per week. she earns 1/3 of her pay on monday and 1/4 on tuesday. how much of her pay does she earn o

n Wednesday
Mathematics
2 answers:
OleMash [197]3 years ago
6 0

Answer:

The answer is 5/12.

Step-by-step explanation:

Multiply 1/3 by 4 and 1/4 by 3 so the denominators are both 12. Then you have 4/12 and 3/12 so add those two fractions to get 7/12. if all three days equals 12/12, and Monday plus Tuesday equals 7/12, the remainder of the pay will be 5/12 on Wednesday.

kipiarov [429]3 years ago
5 0

First, we have to add the fractions.

1/3 + 1/4  = 7/12

12 - 7 = 5

She earns 5/12 of her paycheck on Wednesday

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The scale of a map is 2 cm : 21 km. find the actual distance for 9 cm on the map.
DIA [1.3K]
I hope this helps you

if 2 cm 21 km

9cm ? km

?×2=9×21

?=189÷2

?=94,5 km
8 0
3 years ago
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Test scores are normally distributed with a mean of 500. Convert the given score to a z-score, using the given standard deviatio
Bond [772]

Answer:

The percentage of students who scored below 620 is 93.32%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 500, \sigma = 80

Percentage of students who scored below 620:

This is the pvalue of Z when X = 620. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{620 - 500}{80}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

The percentage of students who scored below 620 is 93.32%.

3 0
3 years ago
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John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid
tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

so

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

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2 years ago
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the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh
Nuetrik [128]

Keywords:

<em>System of equations, variables, hardcover version, paperback version, books </em>

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If from (2) we clear the number of books paperback version we have:

p = 45-h

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply5 * p = 5 (45-h)

So, x = 5 (45-h)

Answer:

x = 5 (45-h)

Option D

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Answer:

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