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LenaWriter [7]
3 years ago
14

Can someone help me with 20

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0
D is subset of Z, so D∩Z=D. hope it helps.
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Find the x-intercept for the line represented by this equation.
saul85 [17]

Answer:

I think the answer is A to you answer

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What is the length of side JK? Leave your answer in simplified radical form.. Single line text.
vladimir1956 [14]
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2 years ago
A ball has a volume of 4 cubic inches (in3). Use the fact that 1 inch is equal to 2.54 cm to convert this volume to cubic centim
Marina86 [1]

Answer:

V = 65.548 cm³

Step-by-step explanation:

We have,

Volume of a ball is 4 cubic inches or 4\ \text{inch}^3.

We know that, 1 inch = 2.54 cm

It is required to convert this volume to cubic centimetre or \text{cm}^3.

4\ \text{inch}^3=4\ \text{inch}^3\times (\dfrac{2.54\ \text{cm}}{1\ \text{inch}})^3\\\\V=65.548\ \text{cm}^3

So, the volume of the ball is 65.548 cm³.

7 0
3 years ago
A shipping company is loading cube shaped crates into a larger cube shaped container the smaller cubes have side lengths 21/2 fe
zheka24 [161]

Answer:

64 crates

Step-by-step explanation:

Smaller Cube Side Length = 2 1/2 feet, or, 2.5 feet

Larger Container (Cube) Side Length = 10 feet

We find volume of larger container and find volume of small crates. We divide the large volume by volume of each crate. This will give us number of crates we can fit.

Volume of Cube = x^3

Where x is the side length of the cube

Now,

Small Crate Volume = (2.5)^3 = 15.625 cubic feet

Large Container Volume = 10^3 = 1000 cubic feet

Number of crates that would fit = 1000/15.625 = 64

So, 64 crates will fit in the largest shipping container

7 0
3 years ago
Mel wants to buy a pair of shoes that costs $120. She has saved $45 and has a job that pays her $10 per hour. The number of hour
maksim [4K]
<h2>Answer: 8</h2>

Step-by-step explanation:

10x+45 > 120\\10x+45-45 > 120-45\\10x > 75\\\frac{10x}{10} > \frac{75}{10} \\x > 7.5

Therefore, Mel has to work at least 7.5 hours or 8 total hours.

3 0
1 year ago
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