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3 years ago

2 1/7 divided by 1 1/14

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

7 0

Answer: 2

Turn 2 1/7 into an Improper Fraction

Multiply 2×7 and get 14. Now add 1 and get 15.

2 1/7 = 15/7

Turn 1 1/14 into an Improper Fraction

Multiply 1×14 and get 14. Now add 1 and get 15.

1 1/14 = 15/14

Your New Problem: 15/7×15/14

Multiply

15/7×15/14=225/98

Simplify

225/98=2.29591836735

Round (Nearest ones)

2.29591836735 rounded equals 2

Final Answer: 2

meriva3 years ago

3 0

Answer:

$2$

Step-by-step explanation:

$2 \frac{1}{7} \div 1 \frac{1}{14} \\ \frac{15}{7} \div \frac{15}{14} \\ \frac{15}{7} \times \frac{14}{15} \\ = \frac{2}{1} = 2$

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The weight of a product is normally distributed with a mean of four ounces and a variance of .25 squared ounces. What is the pro

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Step-by-step explanation:

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3 years ago

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In this assignment, you will explore how the volume is changed when you adjust the height or radius of a cylinder. You will drag

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8 0

2 years ago

Solve for v 12v = 18+6v

jekas [21]

12v = 18+6v

move +6v to the other side

sign changes from +6v to -6v

12v-6v= 18+6v-6v

12v-6v= 18

6v= 18

divide by 6 to get v by itself

6v/6=18/6

Answer:

v= 3

6 0

3 years ago

Use long division to determine the decimal equivalent to 5/9

likoan [24]

5/9 is equal to.5555555555

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3 years ago

Read 2 more answers

Please help me with it is for homework I really need help please help me

Solnce55 [7]

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

$2(s+0.5)+2(s+1.5)$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4$

a. When $s=0,$

then

$2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4$

b. When $s=12,$

then

$2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40$

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.

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3 years ago