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iren [92.7K]
3 years ago
10

Given that you added 5 ug of a purified acid phosphatase to tube a, calculate the amount of acid phosphatase (in ug) that was pr

esent in the 400ul of the wheat germ extract in tube b
Chemistry
1 answer:
Leona [35]3 years ago
5 0

solution:

Amount of purified acid phosphatase added to tube A = 5\mu g(micrograms)\\Amount of acid phosphatase present in 400\mu g of wheat germ extract in tube B=1/100=5x/400\\100x=(0.5)(400)\\X=(0.5)(400)/100=2\mu g\\The amount of acid phosphatase present in 400\mu g of the wheat germ extract in tube B is 2\mu g

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. Calculate the molality of each of the following solutions: (a) 0.710 kg of sodium carbonate (washing soda), Na2CO3, in 10.0 kg
Step2247 [10]

Answer:

a)0.67 molal

b) 5.67 molal

c) 2.82 molal

d) 0.0268 molal

Explanation:

Step 1: Data given

Molality = moles solute / mass solvent

(a) 0.710 kg of sodium carbonate (washing soda), Na2CO3, in 10.0 kg of water—a saturated solution at 0°C

Calculate moles of Na2CO3 =  710 grams / 105.99 g/mol = 6.70 moles

Molality = 6.70 moles / 10 kg = 0.67 molal

(b) 125 g of NH4NO3 in 275 g of water—a mixture used to make an instant ice pack

Calculate moles of NH4NO3 = 125 grams / 80.04 g/mol = 1.56 moles

molality = 1.56 moles / 0.275 kg = 5.67 molal

(c) 25 g of Cl2 in 125 g of dichloromethane, CH2Cl2

Calculate moles Cl2 = 25 grams / 70.9 g/mol= 0.353 moles

Molality = 0.353 moles / 0.125 kg = 2.82 molal

0.372 g of histamine, C5H9N, in 125 g of chloroform, CHCl3

Calculate moles histamine = 0.372 grams / 111.15 g/moles = 0.00335 moles

Calculate molality = 0.00335 moles / 0.125 kg = 0.0268 molal

NOTE: histamine is C5H9N3 not C5H9N

4 0
3 years ago
Part A Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a ch
Basile [38]

Answer:

2HNO3+Ca(OH)2 = Ca(NO3)2+2H2O

Explanation:

The reaction between Nitric acid(HNO3)and Calcium hydroxide(Ca(OH)2) gives Calcium Nitrate( Ca(NO3)2 and Water( H2O)

7 0
3 years ago
Fluorine (F) and bromine (Br) are in the same group on the periodic table. How do atoms of these elements compare when they form
mojhsa [17]

Answer is: Both a fluorine atom and a bromine atom gain one electron, and both atoms become stable.

Fluorine and bromine are in group 17 in Periodic table of elements. Group 17 (halogens) elements are in group 17: fluorine (F), chlorine (Cl), bromine (Br) and iodine (I). They are very reactive and easily form many compounds.

Halogens need to gain one electron to have electron cofiguration like next to it noble gas.

Fluorine has atomic number 9, it means it has 9 protons and 9 electrons.

Fluorine tends to have eight electrons in outer shell like neon (noble gas) and gains one electron in chemical reaction.

Electron configuration of fluorine: ₉F 1s² 2s² 2p⁵.

Electron configuration of neon: ₁₀Ne 1s² 2s² 2p⁶.



3 0
3 years ago
Read 2 more answers
Balance the equation<br> N2O5 + H2 -&gt; NH3 + H2O
Lubov Fominskaja [6]

Answer:

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3 years ago
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