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iren [92.7K]
3 years ago
10

Given that you added 5 ug of a purified acid phosphatase to tube a, calculate the amount of acid phosphatase (in ug) that was pr

esent in the 400ul of the wheat germ extract in tube b
Chemistry
1 answer:
Leona [35]3 years ago
5 0

solution:

Amount of purified acid phosphatase added to tube A = 5\mu g(micrograms)\\Amount of acid phosphatase present in 400\mu g of wheat germ extract in tube B=1/100=5x/400\\100x=(0.5)(400)\\X=(0.5)(400)/100=2\mu g\\The amount of acid phosphatase present in 400\mu g of the wheat germ extract in tube B is 2\mu g

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