Answer: -
Concentration of PbI₂ = 1.5 x 10⁻³ M
PbI₂ dissociates in water as
PbI₂ ⇄ Pb²⁺ + 2 I⁻
So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.
Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =
= 1.5 x 10⁻³ x 2 M
= 3 x 10⁻³ M
PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.
[Pb²⁺] = 1.5 x 10⁻³ M
So solubility product for PbI₂
Ksp = [Pb²⁺] x [ I⁻]²
=1.5 x 10⁻³ x (3 x 10⁻³)²
= 4.5 x 10⁻⁹
Answer:
For iron
Final temperature = 54,22°C
For copper
Final Temperature = 63.67 °C
Explanation
Hello,
You are using a torch to warm up a block of iron that has an initial temperature of 32°C.
The first you have to know is that the "heat capacity" could simply define as the heat required to go from an initial temperature to a final temperature.
So you need to use the heat capacity equation as follow in the paper.
The equation has to have all terms in the same units, so:
q = 12000 J
s = 0.450 J / g °C
m = 1200 g
Ti = 32 °C
