como se denomina el proceso utilizado para descomponer el agua
The boiling point of a liquid can be raised by adding pressure. Like wise, if you lower the pressure the boiling point goes down. This can be explained by the fact that boiling occurse when the vapor pressure equals the outside pressure so when the outside pressure rises the vapor pressure required for boiling also rises. Vapor pressure is proportional to temperature and therefore temperature needs to increase to make the vapor pressure increase.
I hope this helps. Let me know in the comments if anything is unclear or if you want me to explain anything further.
Answer: short answer short 0.65 / 5.37
15% NaOH by mass is 15g of NaOH in (100-15)g of solution.
No. Of moles of NaOH in solution = 0.65
No of moles of Water in solution = 4.72
Mole Fraction =
(
(Moles of Solvent)
(Moles Of Solute)+(Moles of Solvent)
)
OR
(
(Moles of Solvent)
Total Number Of Moles
)
= 0.65 / 5.37
= 0.121
Explanation:
Hope this helped
Answer: +178.3 kJ
Explanation:
The chemical equation follows:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CaO(s))})+(1\times \Delta H^0f_{CO_2}]-[(1\times \Delta H^o_f_{(CaCO_3(s))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CaO%28s%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H%5E0f_%7BCO_2%7D%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CaCO_3%28s%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-635.1%29%29%2B%281%5Ctimes%20%28-393.5%29%29%5D-%5B%281%5Ctimes%20%28-1206.9%29%29%5D)
The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ
Answer:
they tend to be base
Explanation:
this because when they are manufactured they dont tend to use acid solution
