This is an example of displacement reaction
<u>Explanation:</u>
- The chemical reaction in which the one element replaces the other element in a compound is called a displacement reaction. This reaction is also called a replacement reaction.
AB + C -----> AC +B
2ZnS + 3O2 -----> 2ZnO + 2SO2
- This happens when A is more reactive than B and gives a stable product. Here the zinc sulfide compound reacts with the oxygen element to the stable product of zinc oxide and sulfur dioxide.
- In short, the more reactive element displaces the less reactive element is called a displacement reaction.
Answer:
If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the pressure of the gas decreased by a factor of 3.</em></u>
Explanation:
Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or
P * V = k
To obtain the proportionality factor k you must make the quotient:
k= 3
This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the pressure of the gas decreased by a factor of 3.</em></u>
Answer:
10.1 g of Al are formed
Explanation:
The reaction is:
2AlCl3 --> 2Al + 3Cl2
So 2 moles of aluminun chloride decompose into 2 moles of Al and 3 moles of chlorine.
Ratio is 2:2.
Let's convert the mass of salt into moles (mass / molar mass)
50 g / 133.34 g/mol = 0.374 moles.
As the ratio is 2: 2, if I have 0.374 moles of salt, I would produce the same amount of Al, just 0.374.
Let's convert the moles to mass
(Mol . molar mass)
0.374 mol . 26.98 g / mol = 10.1 g of Al are formed
Ξ
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.
So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
One aluminum atom will cost 0.84 × 10⁻²³ cents.
Explanation:
Aluminium costs 85 cents per 453.592 grams.
number of moles = mass / atomic weight
number of moles of aluminium = 453.592 / 27 = 16.8 moles
To calculate the number of aluminum atoms we use the Avogadro's number:
if 1 mole of aluminum contains 6.022 × 10²³ aluminum atoms
then 16.8 moles of aluminum contains X aluminum atoms
X = (16.8 × 6.022 × 10²³) / 1 = 101.17 × 10²³ aluminum atoms
Now, taking in account the aluminium price, we devise the following reasoning:
if 101.17 × 10²³ aluminum atoms costs 85 cents
then 1 aluminum atom costs Y cents
Y = (1 × 85) / (101.17 × 10²³) = 0.84 × 10⁻²³ cents
Learn more about:
Avogadro's number
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