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Rina8888 [55]
3 years ago
11

John and Lisa collected a sample of ocean water and placed it in a jar. Within a couple of days, the water had evaporated and sa

lt was visible at the bottom of the jar.
This is an example of a
O A solute being dissolved.
B
new substance being formed.
O
С
chemical change
o
D
physical change
Chemistry
1 answer:
omeli [17]3 years ago
8 0

THE Answer is Physical Change.

Explanation:

THANKS BB

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In a voltaic (galvanic) cell, oxidation occurs at the _____ and is where _____ in the salt bridge moves toward.
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In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

<h3>What is Galvanic Cell ?</h3>

Galvanic Cell or Voltaic Cell is an electrochemical cell that converts the energy of spontaneous redox reactions into electrical energy. In galvanic cell oxidation occurs at the anode and reduction occurs at the cathode. The anode is positive and cathode is negative, anode attracts anions from solution in an electrolytic cell.

Thus from the above conclusion we can say that In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

Learn more about the Galvanic Cell here: brainly.com/question/15096829

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Cual es el volumen de la solución de hcl la cual se preparo con 3 gramos de soluto (k) al 14%
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A student uses red litmus paper to test the pH value of different solutions. Which would result in a color change of the litmus
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1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all inter
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3 years ago
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−
Lady bird [3.3K]

Answer : The molarity after a reaction time of 5.00 days is, 0.109 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 9.7\times 10^{-6}M^{-1}s^{-1}

t = time taken  = 5.00 days

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.110 M

Now put all the given values in above equation, we get:

9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)

[A]=0.109M

Hence, the molarity after a reaction time of 5.00 days is, 0.109 M

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3 years ago
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