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Novay_Z [31]
3 years ago
9

Is 1/2*4/5 less than 4/5

Mathematics
1 answer:
kati45 [8]3 years ago
4 0
No hope this helps bc it’s being multiplied and even then u simplify
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The sum of two
sergeinik [125]

Answer:

63

Step-by-step explanation:

let the two numbers be x,y (x>y)

Then x+y = 16 and x-y = 2

We know that (x+y)^2 - (x-y)^2 = 4xy

So 4xy = 16^2 - 2^2 => 4xy = (16+2)(16–2)

So xy = 18×14/4 = 63

Product of the numbers = 63

8 0
3 years ago
Write a quadratic equation with 0, -8
Ludmilka [50]
If 0, and -8 are the roots of the quadratic equation we can write
(x-0)(x+8)=0
x(x+8)=0
x²-8x=0
4 0
3 years ago
One card is drawn at random from a deck of 52 cards. The first card is not replaced, and a second card is drawn. (Enter your pro
andriy [413]

Answer:

We have a 52 card deck:

a. Find the probability that both cards are clubs.

The probability of drawing a club will be equal to the quotient between the number of clubs in the deck divided by the total number of cards in the deck.

We initially have 13 clubs and 52 cards, then the probability of drawing a club in the first draw is:

p1 = 13/52.

Now the probability of drawing a club in the second draw will be:

p2 = 12/51

Where each number is decreased by one because we already drew a card, and that card was a club.

Then the probability of both events happening will be equal to the product of the individual probabilities:

P = p1*p2 = (13/52)*( 12/51) = 0.059

b. Find the probability that the first card is a spade and the second is a club.

Same as before, the probability of first drawing a spade is:

p1 = 13/52

And the probability of drawing a club in the second draw will be:

p2 = 13/51

This case differs from the prior one because for the second draw we have 13 clubs in the deck, and as we already drew one card (that was not a club) the total number of cards in the deck is 51.

Now the joint probability will be:

P = p1*p2 = (13/52)*(13/51) = 0.064

3 0
3 years ago
Which answer choice best describes why the relation is a function or is not a function?
Jobisdone [24]

The relation is not a function because the value 3 in the domain is paired with two different values in the range.

Good luck!!!

5 0
3 years ago
Given congruent triangles ΔABC ≅ΔDEF where AB = 11, BC = 5, and DE = 6x-7. Find the value of x.
Sidana [21]

Answer: Congruent angles are angles that have the same measure. ... y = 67 x = 180 – 67 = 113. 2. x = ______ y = ______. 3x – 5 = 127. +5 +5. 3x = 132 ... Find the measure of the angle and give the reason for knowing it. ... Solve for the unknown values: ... 2) AD. 3) AB. 4) BC. 24. In ΔABC, If CA ≅ CB and m∠A = 50, find the m∠B.

5 0
3 years ago
Read 2 more answers
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