Is 1/2*4/5 less than 4/5

Mathematics

1 answer:

kati45 [8]3 years ago

4 0

No hope this helps bc it’s being multiplied and even then u simplify

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Please help me!! -6+x/4=-5

damaskus [11]

y= 4 hope this helps :)

8 0

3 years ago

A truck is being filled with cube-shaped packages that have side lengths of 1/4 foot. The part of the truck that is being filled

n200080 [17]

Answer:

24000 pieces.

Step-by-step explanation:

Given:

Side lengths of cube = $\frac{1}{4} \ foot$

The part of the truck that is being filled is in the shape of a rectangular prism with dimensions of 8 ft x 6 1/4 ft x 7 1/2 ft.

Question asked:

What is the greatest number of packages that can fit in the truck?

Solution:

First of all we will find volume of cube, then volume of rectangular prism and then simply divide the volume of prism by volume of cube to find the greatest number of packages that can fit in the truck.

$Volume\ of\ cube =a^{3}$

$=\frac{1}{4} \times\frac{1}{4}\times \frac{1}{4} =\frac{1}{64} \ cubic \ foot$

Length = 8 foot, Breadth = $6\frac{1}{4} =\frac{25}{4} \ foot$ , Height = $7\frac{1}{2} =\frac{15}{2} \ foot$

$Volume\ of\ rectangular\ prism =length\times breadth\times height$

$=8\times\frac{25}{4} \times\frac{15}{2} \\=\frac{3000}{8} =375\ cubic\ foot$

The greatest number of packages that can fit in the truck = Volume of prism divided by volume of cube

The greatest number of packages that can fit in the truck = $\frac{375}{\frac{1}{64} } =375\times64=24000\ pieces\ of\ cube$

Thus, the greatest number of packages that can fit in the truck is 24000 pieces.

7 0

3 years ago

If a rectangle is 2 meters more than its width, and the area of it is 80 square meters, what is the length and width?

bezimeni [28]

Ok I think it means that the length $l$ of the rectangle is 2 m more than is width $w$ ...
The area is A= $l*w=(w+2)*w=80$
so: $w^{2} +2w-80=0$
Solving this equation (using the quadratic formula) you get 2 solutons. The only acceptable is the positive one, i.e. $w=8 m$ , the length will then be $l=w+2=8+2=10m$ .