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3 years ago

Which equation represents a line that passes through (-9, -3) and has a slope of -6?

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - 6 and (a, b) = (- 9, - 3), so

y - (- 3) = - 6(x - (- 9)), that is

y + 3 = - 6(x + 9)

Jobisdone [24]3 years ago

6 0

Answer:

y+3=-6(x +9)

Step-by-step explanation:

equation represents a line that passes through (-9, -3) and has a slope of -6is:

y+3=-6(x +9)

because : The equation of a linear function in point-slope form is: y – y1 = m(x – x1) ....m : the slope

The point is A (x1 , y1)

you have m = - 6 x1 = -9 y1 = -3

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Find the first four terms of the sequence given by the following. aₙ=43-3(n-1) n=1,2,3. . .

Serggg [28]

Given :-

The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

The first four terms of the sequence.

Solution :-

The given expression is $/$

→ aₙ=43-3(n-1)

where n > 0

Finding the first term :

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

Finding the second term :

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

Finding the third term :

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

Finding the fourth term :

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

Hence the first four terms of the sequence are 43 , 40 , 37 and 34 .

I hope this helps . Let me know if you need further clarification .

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