Let us set up some variables:
Now let us set up some equations based on the facts:
- length of rectangle is 4 times its width --> L = 4W
- perimeter of rectangle is 80 --> 2L + 2W = 80
Equations:
L = 4W -- equation 1
2L + 2W = 80 -- equation 2
Plug the value of L from equation 1 into equation 2
2(4W) + 2W = 80
8W + 2W = 80
10W = 80
W = 8 -- equation 3
Plug the value of W from equation 3 into equation 1:
L = 4W = 4 * 8 = 32
Therefore the length is 32 and the width is 8.
Hope that helps!
Answer:
80 in.²
Step-by-step explanation:
The total surface area of the pyramid is the sum of the area of the base and the areas of the 4 triangular sides.
Square: area = s²
Square: side = 4 in.
Triangular side: area = bh/2
Triangular side: base = 4 in.; height = 8 in.
Area of the base: s² = (4 in.)² = 16 in.²
Total area of the 4 triangular sides: 4 × bh/2 = 2bh = 2 × 4 in. × 8 in. = 64 in.²
Surface area = 16 in.² + 64 in.² = 80 in.²
AC= 10cm because B is the half point between A and C so your adding AB= 4.5 cm and BC= 5.5 cm you get a total of 10 cm, so your answer would be 10 cm
Answer: 20
Step-by-step explanation:
2x^2 + 4y=
2(2)^2 + 4(3)=
2(4)+12=
8+12=20
Answer:
see explanation
Step-by-step explanation:
(a)
← divide numerator and denominator by 4
= 
= 0.8
(b)
→ divide numerator and denominator by 5
= 
= 0.7
(c)
← divide numerator and denominator by 4
= 
= 1.5
