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MakcuM [25]
3 years ago
7

A hydrated salt is a solid that includes water molecules within its crystal structure. A student heated a 12.10-gram sample of a

hydrated salt to a constant mass of 5.41 grams. What percent by mass of water did the salt contain?
Chemistry
1 answer:
sveticcg [70]3 years ago
5 0

Answer : The percent by mass of water the salt contain is, 55.3 %

Explanation : Given,

Mass of hydrated salt = 12.10 g

Mass of salt = 5.41 g

First we have to calculate the mass of water.

Mass of water = Mass of hydrate salt - Mass of salt

Mass of water = 12.10 g - 5.41 g

Mass of water = 6.69 g

Now we have to calculate the percent by mass of water the salt contain.

\text{Percent by mass of water}=\frac{\text{Mass of water}}{\text{Mass of hydrate salt}}\times 100

Now put all the given values in this expression, we get:

\text{Percent by mass of water}=\frac{6.69g}{12.10g}\times 100

\text{Percent by mass of water}=55.3\%

Therefore, the percent by mass of water the salt contain is, 55.3 %

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Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.

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