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yuradex [85]
3 years ago
8

What happens when a catalyst is used in a chemical reaction

Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0
<span>The reaction rate increases.

Why </span><span>Well a catalyst usually lower the activation barrier in an energy diagram. The lower and smaller that gap means the reaction is taking place rapidly compared to when that activation barrier gap is higher. </span>

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Write the formula for the conjugate base for the following acids. <br>Thank you ​
Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+      

b) H20+ H20 --> OH-  + H30+

C)H2PO3-  + H20--> HPO3 2-   + H30+

d) HSO4- + H20 -->  SO4 2- + H30+

E) HCL02 + H20 --> CLO02 -   + H30+

7 0
4 years ago
Read 2 more answers
Is the atomic number the lesser or the greater of the numbers for each atom on the periodic table?
SOVA2 [1]
Lesser. atomic number means proton number
3 0
3 years ago
List the objects from the smallest to the largest mass.
ddd [48]

i need help ls i thank its book 500 grams

3 0
2 years ago
If excess ammonium sulfate reacts with 20.0g of calcium hydroxide how many grams of ammonia are produced
bagirrra123 [75]
The reaction between ammonium sulfate and calcium hydroxide is given below. 
            (NH₄)₂SO₄ + Ca(OH)₂ --> 2NH₃ + CaSO₄ + 2H₂O
From the balance equation, we can conclude that every 74 g of calcium sulfate reacted with enough amount of ammonium sulfate will yield 34 grams of ammonia. From the given amount,
               (20 g calcium sulfate) x (34 grams ammonia / 74 g calcium sulfate)
                               = <em>9.19 g ammonia</em>
3 0
4 years ago
What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?
lana [24]

Answer:

The concentration of the solution is 5.8168 × 10^{-4} mol.dm^{-3}

Explanation:

Here, we want to calculate the concentration of the solution.

The unit of this is mol/dm^3

So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3

The number of moles = mass/molar mass

molar mass of AlCO3 = 27 + 12 + 3(16)  = 27 + 12 + 48 = 87g/mol

Number of moles = 33.4/87 = 0.384 moles

This 0.384 moles is present in 660 L

x moles will be present in 1 dm^3

Recall 1 dm^3 = 1L

x * 660 = 0.384 * 1

x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3

7 0
3 years ago
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