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lara31 [8.8K]
3 years ago
13

Which formula represents an asymmetrical molecule ch4 co2 n2 nh3

Chemistry
1 answer:
Karolina [17]3 years ago
8 0

Answer:

NH₃  

Step-by-step explanation:

All the molecules have some degree of symmetry, but only NH₃ is asymmetric with respect to the bond dipoles.

NH₃ has a trigonal pyramidal geometry.

All the N-H bond dipoles point toward the N, so they all have an upward component with no counterbalancing downward component.

The bond dipoles do not cancel, so NH₃ has a molecular dipole.

CH₄ is tetrahedral and symmetrical.

CO₂  and N₂ are linear and <em>symmetrical</em>.

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Which orbital has the lowest energy
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s orbital

Explanation:

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5 0
2 years ago
The ionization of pure water forms _____.
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Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

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One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

4 0
3 years ago
A generator does work on an electric heater by forcing an electric current through it. Suppose 1 kJ of work is done on the heate
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Answer:

The change in internal energy of the heater is 0 kJ

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3 0
3 years ago
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How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

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r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

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q =  <u>1250 N/C x 0.205m</u>²

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q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

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