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3 years ago

Classify each chemical compound listed in the table below.

Chemistry

1 answer:

prisoha [69]3 years ago

4 0

Answer:

Please find attached the table of classification of the chemical compounds, created with Microsoft Word

Explanation:

The given compounds are;

H₂SO₃ is an acid which is known as sulfurous acid

When SO₂ is added to water, we have;

SO₂ + H₂O ⇄ HSO₃ + H⁺

Therefore, H₂SO₃ is ionic

2) HI which is known as hydrogen iodide, dissolves in water as follows

HI (g) + H₂O (l) ⇄ H₃O⁺(aq) + I⁻(aq)

Therefore, HI is able to donate hydrogen ions therefore, it is both acidic and ionic

3) KI is a salt of the alkali metal, potassium, and iodine which is a group 7 element such that it formed by the transfer of electrons from potassium to iodine making it an ionic compound

KI forms a slightly alkaline solution

4) NaClO₃ comprises of the ionic combination of sodium and chlorate ions which dissolves in water as follows;

NaClO₃ → Na⁺(aq) + ClO₃⁻(aq)

Therefore, NaClO₃ is ionic

NaClO₃ is also a strong oxidizing agent, making a Br∅nsted acid

we have;

Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.

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What is the molar mass of the imaginary compound Z(AX3)2

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The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

<h3>How do we calculate molar mass?</h3>

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

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Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI

melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

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3 years ago

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