Classify each chemical compound listed in the table below.
1 answer:
Answer:
Please find attached the table of classification of the chemical compounds, created with Microsoft Word
Explanation:
The given compounds are;
H₂SO₃ is an acid which is known as sulfurous acid
When SO₂ is added to water, we have;
SO₂ + H₂O ⇄ HSO₃ + H⁺
Therefore, H₂SO₃ is ionic
2) HI which is known as hydrogen iodide, dissolves in water as follows
HI (g) + H₂O (l) ⇄ H₃O⁺(aq) + I⁻(aq)
Therefore, HI is able to donate hydrogen ions therefore, it is both acidic and ionic
3) KI is a salt of the alkali metal, potassium, and iodine which is a group 7 element such that it formed by the transfer of electrons from potassium to iodine making it an ionic compound
KI forms a slightly alkaline solution
4) NaClO₃ comprises of the ionic combination of sodium and chlorate ions which dissolves in water as follows;
NaClO₃ → Na⁺(aq) + ClO₃⁻(aq)
Therefore, NaClO₃ is ionic
NaClO₃ is also a strong oxidizing agent, making a Br∅nsted acid
we have;
Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.
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Answer:
50.8 g
Explanation:
Equation of reaction.
From the given information, the number of moles of methane = mass/ molar mass
= 15.4 g / 16.04 g/mol
= 0.960 mol
number of moles of oxygen gas = 90.3 g / 32 g/ mol
= 2.82 mol
Since 1 mol of methane requires 2 moles of oxygen
Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas
Thus, methane serves as a limiting reagent.
2.82 mol oxygen gas will result in 2.82 moles of water
So, the theoretical yield of water = moles × molar mass
= 2.82 mol × 18.01528 g/mol
= 50.8 g