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3 years ago

What is the asthenosphere?

Chemistry

1 answer:

AfilCa [17]3 years ago

4 0

Answer:

None of the Above

Explanation:

The Athenosphere is able to flow but is also part of the UPPER LAYER meaning none of these choices are correct

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Write a poem about one of the elements (preferably Neon or Helium):

stepan [7]

Answer:

hydrogen is the chemical element with the symbol H and atomic number 1. with the standard atomic

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3 years ago

Which of these is the scientific name for the organism? Question 1 options: puma concolor

allochka39001 [22]

Answer:

All of the above

Explanation:

Panthers, pumas, and mountain lions are all the same animal. Just different names. So, all of these would be correct.

3 0

3 years ago

A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate

Dmitry [639]

Answer: The freezing point of solution is -5.11°C

Explanation:

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

$NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)$

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute (NaCl) = 7.57 g

$M_{solute}$ = Molar mass of solute (NaCl) = 58.44 g/mol

$W_{solvent}$ = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

$\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m$

To calculate the depression in freezing point, we use the equation:

$\Delta T=iK_fm$

where,

i = Vant hoff factor = 2

$K_f$ = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

$\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC$

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T=\text{freezing point of water}-\text{freezing point of solution}$

$\Delta T$ = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

$5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC$

Hence, the freezing point of solution is -5.11°C

7 0

4 years ago

What statement would beast describe a digital signal

Assoli18 [71]

Best* and are there answer choic

6 0

4 years ago

A mixture of 10 moles of A, 5 moles of B and 15 moles of C is placed in a one liter container at a constant temperature. The rea

Cloud [144]

Answer:

Equilibrium constant is 0.0873

Explanation:

For the reaction:

A + B ⇄ C

Equilibrium constant is defined as:

K = [C] / [A] [B]

concentrations in equilibrium of each reactant are:

[A] = 10 - X

[B] = 5 - X

[C] = 15 + X

If concentration in equilibrium of B is 9, X is:

[B] = 5 - X = 9 → X = -4

Replacing:

[A] = 10 - (-4) = 14

[B] = 5 - (-4) = 9

[C] = 15 + (-4) = 11

K = 11 / (14×9) = 0.0873

Thus, equilibrium constant is 0.0873

3 0

3 years ago