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r-ruslan [8.4K]
4 years ago
12

Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar.

Mathematics
1 answer:
Gekata [30.6K]4 years ago
5 0
Bonnie would need to mix 1.5mL of soy sauce for every 1mL of vinegar
Bonnie would need to mix 2/3mL of vinegar for every 1mL of soy Sauce

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Can someone help me with this please
ryzh [129]

Answer:

y=4

Step-by-step explanation:

You can ignore the 3 and 6 because this has no y value change(rise over run)

This is a straight horizontal line so the equation is y=4.

Slope=0

4 0
3 years ago
What is the solution to <br> 5x+9-3x=18+15<br><br> A.x=8<br> B.x=12<br> C.x=21<br> D.x=3
Vlad [161]
Your answer will be B) x=12

1)5x-3x
2) move 9 to the other side (change signs)
3)18+15-9
4) 2x= 24 (divide 2 from both sides
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hope this helps
7 0
4 years ago
Read 2 more answers
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
Three out of every five students wore green on St. Patrick's Day. What percent of the students wore green?
aivan3 [116]
60% must be the right answer
6 0
3 years ago
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madam [21]
6/8 n nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
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3 years ago
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