The zeros of the function occur when the graph meet the x-axis so in this case the zeros occur at B ( 0 and 5)
The standard deviation of the frequency distribution is 5.54
<h3>How to determine standard deviation?</h3>
The table of values is given as:
x f(x)
0-3 13
4-7 13
8-11 10
12-15 11
16-19 0
20-23 3
Rewrite the table by calculating the class midpoints:
x f(x)
1.5 13
5.5 13
9.5 10
13.5 11
17.5 0
21.5 3
Start by calculating the mean using:
This gives
Evaluate
The standard deviation is then calculated as:
So, we have:
Evaluate
Solve
Hence, the standard deviation is 5.54
Read more about standard deviation at:
brainly.com/question/15858152
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Answer:
3a:20d+35
3b:35u+49q+56
4a:15+20t
4b:96k+120t+84
5a:24t+108m+60
5b:56q+28b+35
6a:14q+10w+24
6b:54v+99+27t
7a:16g+24+24c
7b:30a+55+50d
(i think thats what they are but the picture is small so its kind of hard to see)
Step-by-step explanation:
(since theres 10 total ill just give an example on how i solved 5a)
5(4d+7)
simplify into: (5•4d)+(5•7)
multiply: (20d)+(35)
since you do not know what d is, you cannot add them
remove parentheses once done:20d+35
(you don't need parentheses since multiplication come before addition but its easier to just use them)
<h2>Hope this helps</h2>
Answer:
68°
Step-by-step explanation:
As BA⊥BD, so ∠ABD = 90°
also, ∠ABD = ∠CBD + ∠ABC
⇒ 90° = 4x + 52° + 8x - 10°
⇒ 12x = 48°
⇒ x = 4°
now,
∠CBD = 4x + 52°
= 4(4°) + 52°
= 68°
Answer:
the cougars scored 1 point and the eagles scored 8 points
Step-by-step explanation:
if the cougars would have scored 3 times more points they would have been at which means they scored 1 point because 1x3=3. and if the eagles scores 7 more points than the cougars they would have scored 8 points because 1+7=8. :)
