All categories

3 years ago

What is the solution to 5x+9-3x=18+15 A.x=8 B.x=12 C.x=21 D.x=3

2 answers:

7 0

Your answer will be B) x=12

1)5x-3x
2) move 9 to the other side (change signs)
3)18+15-9
4) 2x= 24 (divide 2 from both sides
5)x=12

hope this helps

Travka [436]3 years ago

5 0

asdasdasdadasassasa

You might be interested in

The qestion Is the picture below extra point's

LenKa [72]

Answer:

D) y=0.75x+1

Step-by-step explanation:

8 0

2 years ago

Find the Area. Simplify your answer.

Vaselesa [24]

Answer:

Area = $9x^2$ square units

Step-by-step explanation:

Key skills needed: Area of a parallelogram

1) This shape is a parallelogram, and the way to find the area of a parallelogram is:

$A = bh$

A = area

b = base (the side at the bottom

h = the height ( the length that runs from one side to another and makes a right angle)

2) The base (b) would be 3x. The height (h) would also be 3x

3) This means A = $3x(3x)$

3 times 3 is 9 --> and x times x is $x^2$

Therefore the area is --> $9x^2$

Hope you understood and have a nice day!! :D

5 0

2 years ago

What is the slope of the line through (-5, -3) and (-5, -7)?

Paul [167]

Answer:

The answer is undefined.

Step-by-step explanation:

Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.

5 0

3 years ago

What is an equivalent expression for 3(x-12)? * O 3x-12 3x+12 O 3x-36 3x+36

Doss [256]

The correct answer is
3x - 36

7 0

2 years ago

Read 2 more answers

Given matrices A and B shown below, find (3)A+(8)B.

Tasya [4]

Answer:

$\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]$

Step-by-step explanation:

$\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]$

5 0

2 years ago