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Ede4ka [16]
4 years ago
14

If a fox and an eagle eat some of the same organisms in an ecosystem, the relationship between the fox and the eagle could be cl

assified as
Biology
1 answer:
Elan Coil [88]4 years ago
5 0
If a fox and an eagle eat some of the same organisms in an ecosystem, the relationship between the fox and the eagle could be classified as competition. Competition both within and between species is an important topic in ecology, especially community ecology. It is one of many interacting biotic and abiotic factors that affect community structure. It is a major affecting the availability of resources in an ecosystem is the density of individuals, or the number of organisms living in a certain area.
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There was a chemistry lab and they took water samples to be tested.
4 0
3 years ago
Why do gymnosperms and lower vascular plants lack companion cells?​
IRINA_888 [86]

Answer:

Gymnosperms and lower vascular plants have sieve cells as their sieve elements, while sieve tubes are characteristic of flowering plants angiosperms. In gymnosperms, typical companion cells are lacking in the phloem. In gymnosperms, generally the xylem contains only tracheids. Vessels are absent.

Explanation:

did that help?

4 0
3 years ago
-<br> Calculate the molar mass of a gas that has a density of 1.55g/L.
VLD [36.1K]

Answer: 39.86 g/mol

Explanation:

Assuming this gas is at a pressure of 0.99 atm and a temperature of 37 \°C+273.15=310.15 K, we can solve this problem with the Ideal Gas Law equation:

P.V=n.R.T  (1)

Where:  

P=0.99 atm is the pressure of the gas  

V is the volume of the gas  

n the number of moles of gas  

R=0.0821 \frac{atm.L}{mol.K} is the gas constant  

T=310.15 K is the absolute temperature of the gas in Kelvin

On the other hand, we know the density \rho=1.55 g/L is given by a relation between the mass m and the volume V:

\rho=\frac{m}{V} (2)

Then, the mass is:

m=\rho V (3)

Another important fact here is that the molar mass M_{mass} of an element is given by a relation between the mass of that element and the number of moles n it contains:

M_{mass}=\frac{m}{n} (4)

Isolating n:

n=\frac{m}{M_{mass}} (5)

Substituting (5) in (1):

P.V=\frac{m}{M_{mass}}.R.T  (6)

Substituting (3) in (6):

P.V=\frac{\rho V}{M_{mass}}.R.T  (7)

Isolating M_{mass}:

M_{mass}=\frac{\rho V}{PV}RT (8)

Simplifying:

M_{mass}=\frac{\rho}{P}RT (9)

Solving with the given data:

M_{mass}=\frac{1.55 g/L}{0.99 atm}(0.0821 \frac{atm.L}{mol.K})(310.15 K) (10)

Finally:

M_{mass}=39.86 g/mol This is the molar mass of the gas

6 0
3 years ago
When any type of cell is placed in a hypotonic solution which direction does the water flow in? What does that tell you about th
Svetach [21]

to the lower concentration point,

water molecules diffuse into the vacuole and it enlargers. The cell is said to be turgid

6 0
4 years ago
All of the following are examples of limiting factors in an ecosystem except:
ludmilkaskok [199]

Answer:

population density I hope this helps

4 0
2 years ago
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