Question

Solutions for 2x^2+18x=20, worth a TON, please only 100% answers ! Thank u !

Answer 1

Answer:

The solution of the given quadratic equation is 1 and (-10).

Step-by-step explanation:

$2x^2+18x=20$

$x^2+9x=\frac{20}{2}$

$x^2+9x-10=0$

$ax^2+bx+c=0$

Solving equation by quadratic formula:

Here , a = 1,b = 9, c = (-10)

$D=b^2-4ac=(9)^2-4(1)(-10)=121$

$x=\frac{-b+{\sqrt{D}}}{2a}=\frac{(-9)+\sqrt{121}}{2(1)}=1$

$x=\frac{-b-{\sqrt{D}}}{2a}=\frac{(-9)-\sqrt{121}}{2(1)}=(-10)$

The solution of the given quadratic equation is 1 and (-10).