Hello f(x) = 2sin(x) f(<span>π/6) = 1 f'(x) 2cos(x) f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3) The equation of this tangent line is : y= root(3)(x-π/6)+1 y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b m = root(3) and b = </span>1 - π/6(root(x))
