How many roots does a quadratic have if the discriminant if prime?

Mathematics

1 answer:

scZoUnD [109]3 years ago

5 0

"The discriminant is prime?" I haven't heard that one before.

Here are the general rules:

1. a positive discriminant results in two real, unequal roots.

2. a zero discr. results in two real, equal roots.

3. a negative discr. results in two complex roots, which sometimes means two imaginary roots.

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Answer:

$P = 0.1447$

Step-by-step explanation:

Given

$n = 7000$ -- total

$d = 180$ --- defective

$r = 6$ --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

$Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}$

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

$Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}$