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Viktor [21]
4 years ago
11

Where would 13/4 be on the number line

Mathematics
2 answers:
Evgen [1.6K]4 years ago
6 0
Near the right or the mid-way to the left.
Rainbow [258]4 years ago
5 0
13/4 =12/4 +1/4=3+1/4 so it has to be between 3 and 4 on the number line.Hope this helps and thank you for letting me help you ✅
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John sister went shopping with him. She expected to spend $100 on clothes, but only spent $10. Jonah wanted to help her calculat
Mars2501 [29]
Incorrect cuz where did he get the 90 from??
7 0
4 years ago
Read 2 more answers
HELPPP ME ASAPPPP PLEASEEE!!
kaheart [24]

y = 90°

Solution:

The reference image for the answer is attached below.

The sum of opposite interior angles is equal to the exterior angles.

m∠BAC + m∠ACB = 110°

m∠BAC + 70° = 110°

m∠BAC = 110° –  70°

m∠BAC = 40°

m∠BAD + m∠DAC = 40°

x + x = 40°

2x = 40°

Divide by 2 on both sides of the equation.

x = 20°

In triangle DAC,

Sum of all the angles of a triangle = 180°

m∠DAC + m∠ACD + m∠CDA = 180°

20° + 70° + m∠CDA = 180°

90° + m∠CDA = 180°

m∠CDA = 180° – 90°

m∠CDA = 90°

∠CDA and y lies on the straight line. So they form a linear pair.

y + m∠CDA = 180°

y + 90° = 180°

y = 180° – 90°

y = 90°

The value of y is 90°.

7 0
3 years ago
What is the recursive rule for the sequence?
Marrrta [24]

The next term is 1.4 larger than the one before it, so the appropriate choice is

a_{n}=a_{n-1}+1.4 \quad\mbox{where}\ a_{1}=1.4

_____

However, the description

a_{n}=a_{n+1}-1.4 \quad\mbox{where}\ a_{1}=1.4

also correctly describes the relationship between a1 and a2, for example. While this equation is technically correct, it is less useful to work with, so is probably not the expected answer.

4 0
3 years ago
Find the distance between the points (5, -3) and (0, 2).
ohaa [14]

Answer:

Distance between points  (5, -3) and (0, 2) is √50 or 7.07

Step-by-step explanation:

We need to find distance between two points (5,-3) and (0,2)

The distance formula used is:

d= \sqrt {\left( { x_2-x_1 } \right)^2 + \left( {y_2-y_1} \right)^2 }

here

x₁= 5, y₁=-3, x₂=0 and y₂=2

Putting values in the formula:

d= \sqrt {\left( {x_2-x_1} \right)^2 + \left( {y_2-y_1} \right)^2 }\\d= \sqrt {\left( {0-5} \right)^2 + \left( {2-(-3)} \right)^2 }\\d= \sqrt {\left( {-5} \right)^2 + \left( {2+3} \right)^2 }\\d= \sqrt {25+25}\\d= \sqrt {50}\\d= 7.07

So, distance between points  (5, -3) and (0, 2) is √50 or 7.07

7 0
3 years ago
Read 2 more answers
What is the slope of this equation?y= -1/2x −3 Question 2 options: 0 -3 -1/2
storchak [24]

Answer:

-1/2

Step-by-step explanation:

In the equation y=mx+b..

y and x are the coordinates that go into your function

m is the slope

and b is the y intercept

looking at y=-1/2x-3 i can tell that -1/2 is in the place of m which is slope, and -3 is the y intercept.

8 0
3 years ago
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