Answer:
im confused
Step-by-step explanation:
Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer:
5x-8y
Step-by-step explanation:
4x-9y+x+y
=4x+-9y+x+y
=4x+-9y+x+y
=(4x+x)+(-9y+y)
=5x+-8y
=5x-8y
For the given set of numbers:
<span>{1,2,3,4, 5, 6, 7, 8, 9, 10}
the number of elements
n=10
the total number of subsets is given by:
2^10=1024
</span>
Lets say that J is for Jennys messages, B is for Boris’ and E is for Erics (or Ericas?).
79 = J + B + E
J = E - 6
B = 3E
Since both Jenny’s and Boris’ number of text messages has some kind of relation to Eric’s number of messages, we can say that:
79 = E - 6 (Jenny) + 3E (Boris) + E (Eric), so:
79 = E - 6 + 3E + E /combine like terms
79 = 5E - 6 /add 6 to both sides
79 + 6 = 5E /switch sides + combine like terms
5E = 85 /divide both sides by 5
E = 85/5
E = 17
So, Eric sent 17 messages. Lets get back to those equations we made for Jenny and Boris:
J = E - 6 = 17 - 6 = 11
B = 3E = 3 * 17 = 51
And we can check if it adds up: 51 + 11 + 17 = 79, which is what we were supposed to get.
