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3 years ago

What is the volume of a circular cylinder with a base diameter of 6 m and a height of 5 m?

Mathematics

1 answer:

mixas84 [53]3 years ago

6 0

For this case we have that by definition the volume of a cylinder is:
V = ((pi) * (r ^ 2)) * (h).
Where
r: radio
h: height.
Also we have
r: d / 2
Where,
d: diameter.
Substituting we have:
V = ((pi) * ((d / 2) ^ 2)) * (h).
V = (pi) * (((6) / 2) ^ 2) * (5).
V = 45pi m ^ 3
Answer:
The volume of a circular cylinder is:
V = 45pi m ^ 3

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stepan [7]

Answer:

Max's paper airplane flew $\frac{77}{12}$ feet or $6\frac{5}{12}$ feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

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$9\frac{1}{6}=\frac{55}{6}$

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

$2\frac{3}{4}=\frac{11}{4}$

Thus the equation to show how far Max's paper airplane flew is:

$\:\:9\frac{1}{6}-2\frac{3}{4}$

$=\frac{55}{6}-\frac{11}{4}$

$\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$=\frac{110}{12}-\frac{33}{12}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{110-33}{12}$

$\mathrm{Subtract\:the\:numbers:}\:110-33=77$

$=\frac{77}{12}$

$=6\frac{5}{12}$

Therefore, Max's paper airplane flew $\frac{77}{12}$ feet or $6\frac{5}{12}$ feet.

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3 years ago

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mestny [16]

Answer:

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Step-by-step explanation:

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y = (y₁ + y₂)/2

Since midpoint and one endpoint given (10, 4) and (9, -4), the other endpoint:

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this is your answer. If I am right so.

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