(Please vote me Brainliest if this helped!)
- Library
- 6 blocks
- 2.5 blocks
Step-by-step explanation:
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The answer should be the very last option. An equation where the highest exponent of the variable (usually x) is a square (2).
Answer:
sec(theta°)cos(theta°) = 1
Step-by-step explanation:
given data
(theta°) = 225
to find out
sec(theta°)cos(theta°)
solution
as we know that given equation
(theta°) = 225
cos(theta°) will be
cos(225°) = -0.7071 .................................1
so we know
sec(theta°) =
..............2
so put here value of cos(theta°)
sec(theta°) =
sec(theta°) = - 1.4142
so
sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )
sec(theta°)cos(theta°) = 1
so answer is sec(theta°)cos(theta°) = 1
Keep your mom, you only have one. But anyway;
Use the Pythagorean Theorem: A^2 + B^2 = C^2
12^2 + 21^2 = C^2
144 + 441 = C^2
585 = C^2
square root of 585 = approximately 24.2