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Anastasy [175]
3 years ago
15

Perform the operation(s) and write the answer in simplest form.

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
First add the fractions in the parenthesis: 1/2+1/3.. In order to do this find the common denominator, which in this case is 6.  So 3/6+2/6=5/6.  Now you have 5/6/15/4.  Divide the fractions and then simplify to get 2/9.

Hope the explanation helped!

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The circumference of a circle is 18 feet. What is the area
7nadin3 [17]

Answer:

18

Step-by-step explanation:

it does not have an area its an circle so it just 18 feet

really want a crown

8 0
3 years ago
Read 2 more answers
What are the values of x and y given that ABCD ≅ EFGH?
Margarita [4]

Answer:

x = 7

y = 8

Step-by-step explanation:

Since the shapes are similar then <B = <F and <A = <E

<B = <F so

10x + 65 = 135 subtract 65 from both sides

10x = 70 divide both sides by 10

x = 7

<A = <E so

4y - 4 = 28 add 4 to both sides

4y = 32 divide both sides by 4

y = 8

7 0
3 years ago
What is the value of x in the equation x - y = 30, when y = 15?<br> O4<br> O 8<br> O 80<br> O 200
olganol [36]

\frac{1}{5}x -  \frac{2}{3} y = 30  \\

Putting the value of Y = 15

\frac{1}{5} x -  \frac{2}{3}  \times 15 = 30  \\   \frac{1}{5} x = 30  +  10 \\  \frac{1}{5} x = 40 \\ x = 5 \times 40 \\  x = 200

So, X = 200

6 0
2 years ago
F(x)=2x+3/4x+5 find f(-9)<br><br>pls solve it ​
Marysya12 [62]

Answer:

15/31

Step-by-step explanation:

substitute -9 were there's x in the function

f(-9)=2(-9)+3/4(-9)+5

=-18+3/-36+5

=-15/-31

the negatives cancel giving you

15/31

4 0
3 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
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