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mojhsa [17]
2 years ago
7

An urn contains green and red balls. six balls are randomly drawn from the urn in succession, with replacement. that is, after e

ach draw, the selected ball is returned to the urn. what is the probability that all balls drawn from the urn are green? round your answer to three decimal place
Mathematics
1 answer:
ANEK [815]2 years ago
7 0
0.022  might be the answer.
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If 6 pipes fill a tank in 120 minutes, then 5 pipes can fill it in how many minutes​
Marianna [84]

Answer:

<u>It'll</u><u> </u><u>take</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u><u>minutes</u><u> </u><u>for</u><u> </u><u>5</u><u> </u><u>pipes</u><u>.</u>

Step-by-step explanation:

{ \sf{6 \: pipes = 120 \: mins}} \\ { \sf{5 \: pipes = ( \frac{6}{5}  \times 120) \: mins}} \\  \\  = { \sf{144 \: mins}}

but practically, it seems to be abnormal. if 6 pipes take 120 mins, 5 pipes must takes a time greater than 120 mins cause amount of water flowing to the tank is decreasing.

<em>B</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>p</em><em>o</em><em>s</em><em>s</em><em>i</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>p</em><em>r</em><em>e</em><em>s</em><em>s</em><em>u</em><em>r</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>w</em><em>a</em><em>t</em><em>e</em><em>r</em><em> </em><em>w</em><em>a</em><em>s</em><em> </em><em>i</em><em>n</em><em>c</em><em>r</em><em>e</em><em>a</em><em>s</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>a</em><em>s</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>f</em><em>i</em><em>v</em><em>e</em><em> </em><em>p</em><em>i</em><em>p</em><em>e</em><em>s</em><em>,</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em>'</em><em>s</em><em> </em><em>w</em><em>h</em><em>y</em><em> </em><em>i</em><em>t</em><em> </em><em>t</em><em>a</em><em>k</em><em>e</em><em>s</em><em> </em><em>a</em><em> </em><em>t</em><em>i</em><em>m</em><em>e</em><em> </em><em>l</em><em>e</em><em>s</em><em>s</em><em> </em><em>t</em><em>h</em><em>a</em><em>n</em><em> </em><em>1</em><em>2</em><em>0</em><em> </em><em>m</em><em>i</em><em>n</em><em>s</em><em>.</em><em> </em><em>(</em><em>t</em><em> </em><em><</em><em> </em><em>1</em><em>2</em><em>0</em><em>)</em>

5 0
2 years ago
Read 2 more answers
Given the parent functions f(x) = 5x − 1 and g(x) = 3x − 9, what is g(x) − f(x)?
MissTica
F(x) = 5x − 1

and g(x) = 3x − 9


g(x) - f(x) = (3x − 9) - (5x − 1) ===> -2x-8
5 0
3 years ago
Peggi put some hairbows in 6 party bags. Her sister Tori put 2 more
irga5000 [103]

Answer:

Peggi put a total of 18 hair bows in the bag

Step-by-step explanation: There at six bags with an unknown amount of hairbows in each bag. You add 2 to each bag and you will end up getting 12 hairbows from her sister because 6x2=12. then you subtract the total (30) from her sister Toris amount (30-12) this equals 18.

5 0
3 years ago
Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.
Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If x + \dfrac{1}{x} is an integer

∴ \left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

x + \dfrac{1}{x}

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}

By simplification of the cube of the given integer expressions, we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )

Therefore, we have;

\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}

By rearranging, we get;

x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )

Given that  x + \dfrac{1}{x} is an integer, from the closure property, the product of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 is an integer and 3\cdot \left (x + \dfrac{1}{x} \right ) is also an integer

Similarly the sum of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

\therefore x^3 + \dfrac{1}{x^3} =   \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer.

4 0
3 years ago
3. In your own words, describe what a response variable is in an experiment.
Fofino [41]

Answer:

A response variable is a dependent variable. it is a variable which is measured and explained in an experiment

Step-by-step explanation: a response variable must always gwith explanation variable.

3 0
2 years ago
Read 2 more answers
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