Question

StartFraction (negative 7) squared Over (negative 7) Superscript negative 1 EndFraction

Answer 1

Answer:

-343

Step-by-step explanation:

Given the expression:   $\dfrac{(-7)^2}{(-7)^{-1}}$

You will notice that the terms in the numerator and denominator have the same base (-7).

This makes it very easy to simplify by applying the division law of indices.

$\dfrac{a^x}{a^y} =a^{x-y}$

Therefore:

$\dfrac{(-7)^2}{(-7)^{-1}}=(-7)^{2-(-1)}\\=(-7)^{2+1}\\=(-7)^3\\=-7 X -7 X -7\\=-343$

Answer 2

Answer:

-343

Step-by-step explanation: