Answer: There are 19 classes
Step-by-step explanation:
divide the total amount amount of students by the amount of students in each class
The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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18÷(5-2)
18÷3
6 is the answer
Answer:
an = -3·2^(n-1)
Step-by-step explanation:
The first term is a1 = -3.
The common ratio is r = -6/-3 = 2.
The given formula tells you the formula for this sequence is ...
an = -3·2^(n-1)
