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3 years ago

Which of these statements best describes the difference between electromagnetic and gravitational forces in the solar system?

Physics

2 answers:

kodGreya [7K]3 years ago

5 0

It's B-<span>Electromagnetic forces are stronger than gravitational forces</span>

LUCKY_DIMON [66]3 years ago

3 0

Answer:

Electromagnetic forces are stronger than gravitational forces.

Explanation:

Electromagnetic and gravitational forces both are fundamental forces present in nature. The force that exists between the charged particles are electromagnetic forces while the force that exists between two objects in the universe is called gravitational force.

The one of the difference between these two forces is that the gravitational force is always attractive while the electromagnetic force can be attractive or repulsive.

Electromagnetic forces are stronger than gravitational forces. It is approximate 10³⁹ times stronger than gravitational force. Hence, the correct option is (b).

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What property of matter do we consider when deciding whether to buy a half-gallon of milk at the store versus a gallon of milk?

Mrac [35]

Liquified matter maybe.

7 0

3 years ago

Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their

Anna35 [415]

Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v= $\frac{s}{t}$
we get
V₁= $\frac{100}{10}$
V₁=10m/s

V₂= $\frac{100}{10.2}$
V₂=9.8m/s

V₃= $\frac{100}{10.4}$
V₃=9.61 m/s

V₄= $\frac{100}{10.6}$
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43

8 0

3 years ago

Which of the following metals require ultraviolet light to exhibit the photoelectric effect?The options available: a. Cs, work f

Eddi Din [679]

Answer:

b. AG, work function=4.74eV

Explanation:

Ultraviolet light starts at the end of the visible light spectrum, where violet light ends:

$\lambda=380 nm =3.8\cdot 10^{-7}m$ (wavelength of lowest-energy ultraviolet light)

So, the lowest energy of ultraviolet light can be found by using the formula

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

Substituting,

$E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.8\cdot 10^{-7} m}=5.23\cdot 10^{-19}J$

And keeping in mind that

$1 eV = 1.6\cdot 10^{-19}J$

This energy converted into electronvolts is

$E=\frac{5.23\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=3.27 eV$

The work function of a metal is the minimum energy needed to extract a photoelectron from the surface of the metal. Therefore, the metals that exhibit photoelectric effect are the ones whose work function is larger than the energy we found previously, so:

b. AG, work function=4.74eV

Because for all the other metals, visible light will be enough to extract photoelectrons.

7 0

3 years ago

Lonnie pitches a baseball of mass 0.500 kg. The ball arrives at home plate with a speed of 35.0 m/s and is batted straight back

Andreyy89

Answer:

Explanation:

The impulse equation is

Δp = FΔt, where Δp = final momentum - initial momentum, F is the Force exerted on an object, and Δt is the change in time. In this equation,the entire right side defines the impulse. In other words, FΔt is the impulse; thus the change in momentum an object experiences is due to its change in impulse and is directly proportional to it.

Therefore, once we find the change in momentum, that is the impulse the object experiences. Δp = final momentum - initial momentum, where

p = mv and p is momentum.

$p_f=(.500)(50.0)$ so