Answer:
Explanation:
With a initial velocity is zero, kinematics equation is:
A 3.1 kilogram gun initially at rest is free to move. When a 0.015-kilogram bullet leaves the gun with a speed of 500. meters pe
r second, what is the speed of the gun?
1 answer:
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The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.
<h3>What is the law of conservation of momentum?</h3>According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Unit conversion:
1 metric tons = 1000 kg
Given data;
m₁= 11.6 metric ton =11600 kg
m₂ = 23.2 metric ton = 23200 kg
Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.
Considering energy conservation;
From the conservation of momentum principle;
Hence, the final common speed of the two carts will be 69.3 m/sec.
To learn more about the law of conservation of momentum refer;
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