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sergejj [24]
3 years ago
11

plz solve, I will give brainliest, There are three consecutive integers. The sum of the first two is 51 more than the third. Fin

d the integers.
Mathematics
2 answers:
Lina20 [59]3 years ago
8 0
X+x+1=51+x+2
2x+1=x+53
x=52

integeers are 52. 53 and 54
Natasha2012 [34]3 years ago
8 0

The integers are \boxed{52}, \boxed{53} and \boxed{54}.

Further explanation:

Given:

The sum of the first two is 51 more than the third.

Explanation:

Consider the first integers as x.

So the second integers is x+1.

Therefore, the third integers is x+2.

Given that the sum of first two numbers is 51 more than the third.

\begin{aligned}\left( x \right) + \left( {x + 1} \right) &= 51 + \left( {x + 2} \right)\\x + x + 1 &= 51 + x + 2\\2x + 1 &= 53 + x\\2x - x &= 53 - 1 \\x&= 52\\\end{aligned}

The first integer is 52.

The second integer can be calculated as,

\begin{aligned}{\text{Second integer}} &= x + 1\\&= 52 + 1\\&= 53\\\end{aligned}

The second integer can be calculated as,

\begin{aligned}{\text{Third integer}}&= x + 2\\&= 52 + 2\\&= 54\\\end{aligned}

Hence, the integers are \boxed{52}, \boxed{53} and \boxed{54}.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Three consecutive, consecutive, sum, addition, integers, more, 51 more, consecutive integers, first two.

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