Question

plz solve, I will give brainliest, There are three consecutive integers. The sum of the first two is 51 more than the third. Find the integers.

Answer 1

X+x+1=51+x+2
2x+1=x+53
x=52

integeers are 52. 53 and 54

Answer 2

The integers are $\boxed{52}$, $\boxed{53}$ and $\boxed{54}$.

Further explanation:

Given:

The sum of the first two is 51 more than the third.

Explanation:

Consider the first integers as $x$.

So the second integers is $x+1.$

Therefore, the third integers is $x+2.$

Given that the sum of first two numbers is 51 more than the third.

$\begin{aligned}\left( x \right) + \left( {x + 1} \right) &= 51 + \left( {x + 2} \right)\\x + x + 1 &= 51 + x + 2\\2x + 1 &= 53 + x\\2x - x &= 53 - 1 \\x&= 52\\\end{aligned}$

The first integer is 52.

The second integer can be calculated as,

$\begin{aligned}{\text{Second integer}} &= x + 1\\&= 52 + 1\\&= 53\\\end{aligned}$

The second integer can be calculated as,

$\begin{aligned}{\text{Third integer}}&= x + 2\\&= 52 + 2\\&= 54\\\end{aligned}$

Hence, the integers are $\boxed{52}, \boxed{53}$ and $\boxed{54}.$

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Three consecutive, consecutive, sum, addition, integers, more, 51 more, consecutive integers, first two.