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Digiron [165]
3 years ago
5

Who needs special prayer

Mathematics
2 answers:
kupik [55]3 years ago
8 0

Answer:

me, please me

Step-by-step explanation:

I'm going through court cases because my dad raped me and so on

vivado [14]3 years ago
4 0

Answer: Everyone does mate!

Step-by-step explanation: EVERYTHING IS EVERYTHING

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The LCM of two numbers is 60.the sum of the numbers is 32
mihalych1998 [28]
Write down some possibilities of the 2 numbers that add up to 32 first.
16+16, 15+17, 14+18, 13+19, 12+20

12 and 20 works because 12*5=60 and 20*3=60

Your answer is 12 and 20 (:
8 0
2 years ago
Read 2 more answers
Use properties to evaluate 7/5(1/4 divide 7/4)(-10)
cricket20 [7]
The answer isssssss c -2
3 0
3 years ago
Solve 2(x-1)+2(3x-1)=0 ​
sertanlavr [38]

Answer:

(x-1)+2(3x-1)=0

2x-2+6x-2=0

8x-4=0

8x=4

x=4/8

×=1/2

8 0
2 years ago
Find the rate of change
andrezito [222]

Step-by-step explanation:

(x1,y1) = (-1,-1)

(x2,y2) = (2,-2)

m = (y2 - y1)/(x2 - x1)

m = (-2 + 1)/(2 + 1)

m = -1/3

Option → C

8 0
2 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
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