2 + 0.8
oof the first time i did it, i was thinking of something else
sorry
Answer:
(a) f(0) = 1
(b) f(3) = 5 (I'm not sure about this one, it's either this or undefined)
(c) f(-2) = 3
(d)
(e)
(f)
(g) DNE, because the limit of x--> 1 from the left is 2, and the limit from the right is 1. Because they don't approach the same value from both sides, the limit doesn't exist.
-5 because it is closest to zero and -17 is farther than zero on a number line :) <span />
Actually Welcome to the concept of straight lines.
==> y-y1 = m(x-x1)
==> y = mx+c
these two are the straight line equation, so we get as,
=> 0-0 = m(8-(-7)
==> 0 = m(15)
==> hence, 15m = 0
Answer:
f(a + h) = a^2 + h^2 + 2ah + 3a + 3h + 5
Step-by-step explanation:
f(x)=x² + 3x + 5
f(a+h) = (a + h)^2 + 3(a + h) + 5
f(a + h) = a^2 + 2ah + h^2 + 3a + 3h + 5
f(a + h) = a^2 + h^2 + 2ah + 3a + 3h + 5