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SCORPION-xisa [38]

3 years ago

15

Factor 10x2+15x-70 , this is the last factoring problem I’ll post relating to the test but I thank you all for your help once ag

ain.

1 answer:

zepelin [54]3 years ago

5 0

10x²+15x-70= 5(2x² +3x - 14)= 5(2x+7)(x -2)

(2x+7)(x -2) = 2x²+7x-4x-14 = 2x²+3x-14

correct answer is A

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3 years ago

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4 years ago

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jeyben [28]

The meaning of the question is

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3 years ago

What is the square root of 25

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3 0

3 years ago

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Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students

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<span>In general, the height of a projectile is given by

</span> $h= -\frac 1 2 g t^2 + v t + h_0$
<span>
where </span> $h$ is the height at time $t$ of a projectile shot upward at velocity $v$ from initial height $h_0$ <span>.

The acceleration of gravity </span> $g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.$ <span> We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

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We have MKS units, positive (upward) velocity and an initial height of 0.

</span> $h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t$
<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second. Not metric, velocity +50, initial height zero.

</span> $h= -16t^2 + 50t$
<span>
Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

</span> $h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19$
<span>
Group D drops a tennis ball from a height of 50 feet.

</span> $h= -16 t^2 + 50$
<span>

</span>

6 0

4 years ago

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