Answer:
Part a) Daniel's age is 2 years
Part b) Kevin's age is 8 years
Step-by-step explanation:
<u><em>The question is </em></u>
Part a) How old is Daniel?
Part b) How old is Kevin?
Let
x ----> Kevin's age
y ----> Daniel's age
we know that
-----> equation A
----> equation B
Equate equation A and equation B
solve for y
therefore
Daniel's age is 2 years
<em>Find the value of x</em>
substitute the value of y in any of the two equations
therefore
Kevin's age is 8 years
We are given D (7, -3) and D'(2, 5).
SAppy the transformation
D'(x,y) → D(x-5, y+8).
Then
x=7 → x=7-5 = 2
y=-3 → y=-3+8 = 5
Answer: D (x-5, y+8) → D'
Answer:
C. 3.33 hours
Step-by-step explanation:
Use the algebra work equation:
= 
+ 
, where tb is the time to work together, t1 is the time it takes one person, and t2 is the time it takes the other person
Plug in the values we know:
= 
+ 
= 
+ 
= 
20 = 6tb
3.33 = tb
So, it would take them 3.33 hours when working together.
The maximum value it can be would be 100%. The only times that it could be this high is when there is only a class on the frequency distribution table. Another way, is that there is only one column variable on the table (& or if there is only one row.) Any other time is will be less, but the maximum stays 100%.
Answer:
Option (B)
Step-by-step explanation:
From the given table,
With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.
Interval (0, 1) lies in the domain of the function in which the y-values of the function are,
At x = 0,
f(0) = -6
At x = 1,
f(1) = 0
Therefore, values of the given function are increasing in the interval of (0, 1).
Option (B) will be the correct option.
