All categories

3 years ago

If a plane flies 612 km per hour, approximately how many kilometres will it travel in 13 hours?

Mathematics

2 answers:

zaharov [31]3 years ago

7 0

$612km...........1h \\ x...................13h \\ \\ x=\frac{612*13}{1} \\ \\ \boxed{x=7956km}$

rusak2 [61]3 years ago

4 0

$612 \frac{km}{hr} * 13 = 7,956 \frac{km}{hr}$

You might be interested in

Una ciudad tenía 8000 habitantes a final del año 2000. Cada año su población se incrementa en un 0.5 %

Digiron [165]

Answer:

The correct answer is 2030.

Step-by-step explanation:

To start we must analyze the information we have.

We know that a city has 8000 inhabitants and that each year this number increases by 0.5%. That means that each year it has 40 more inhabitants:

(8000 . 0,5) : 100 = 40

Having this information we could do a cross multiplication:

1 year ------- 40 inhabitants

x years ------- 81200

81200 = 40.x

x = 81200 : 40

x = 2030

In this way we can verify that the correct answer is 2030.

4 0

3 years ago

Answer both questions!

vodomira [7]

1) What is the equation for the line?
slope = 16/2 = 8

answer
equation
y = 8x

2) What is the equation of a line with a slope of 3 and a point (3, 1) on the line?

Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.

y - 1 = 3(x - 3)
y - 1 = 3x - 9
y = 3x - 8

answer
y = 3x - 8

3 0

3 years ago

HELP!!!!!

Nata [24]

Answer:

Step-by-step explanation:

identify two points on the graph:

1. (0, 4)

2. (-2, 2)

use slope formula: (y² - y¹) / (x² - x¹)

1. (2 - 4) / (-2 - 0) = -2 / -2 = 1

slope = 1

8 0

3 years ago

Read 2 more answers

Solve the equation -4x+12=-4 for x .

mihalych1998 [28]

-4x +12 -12 = -4 -12
-4x = -16
x = 4

4 0

3 years ago

Read 2 more answers

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago