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Zinaida [17]
3 years ago
7

Many unversities and colleges have instituted supplemental instruction (SI) programs, in which student facilitator meets regular

ly with a small group of students enrolled in the course to promote discussion of course material and enhance subject mastery. Suppose that students in a large statistics course are randomly divided into a control group group that will not participate in SI and a treatment group that will participate. At the end of the term each student’s total score in the course is determined.
A) Are the scores from the SI group a sample from an existing population? If so, what is it? If not, what is the relevant conceptual population?
B) What do you think is the advantage of randomly dividing the students into the two groups rather than letting each student choose which group to join?
C) Why didn’t the investigators put all students in the treatment group?
Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

Step-by-step explanation:

SUPPLEMENTAL INSTRUCTION PROGRAMS

- Students in a large statistics course are randomly divided into a control group and an experimental/treatment group. At the end of the term, each student's score in the course is examined

(A) The scores from the SI (Experimental) group are not a sample from an existing population. They are data from a group in a sample, hence the sample here is the number of students tested in this experiment and that equates to all the students in the large Statistics course/class.

- The relevant conceptual population would be all students in the university, since the general purpose or statement of this experiment is to see the effect of SI programs implemented in universities.

(B) The advantage of the random (unintentional) division of the students into control and experimental groups is that results or scores from the groups will be unbiased.

If you let each student choose a group, there is a high probability that the serious students will all join the SI group while the unserious ones will choose to be in the control group.

There is also a high probability that brilliant/pompous students will ignore the supplemental instruction program while students with low and medium intelligence quotient (IQ) will embrace it.

It is also possible that students will join whatever group their friends join.

These and other biases will defeat the aim of the experiment.

(C) The investigators didn't put all students in the sample into the experimental group because the difference or impact of the SI program needs to be known; whether positive or negative. Dividing them into the 2 groups lets the investigators know if there is a difference in the scores of students in the two groups.

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Answer:

Step-by-step explanation:

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We see we have a snowball, which is a sphere. We are talking about the surface area of this sphere which has a formula of

S=4\pi r^2

In the problem we are given diameter, not radius. What we know about the relationship between a radius and a diameter is that

d = 2r so

\frac{d}{2}=r Now we can have the equation in terms of diameter instead of radius. Rewriting:

S=4\pi(\frac{d}{2})^2 which simplifies to

S=4\pi(\frac{d^2}{4}) and a bit more to

S=\pi d^2 (the 4's cancel out by division). Now that is a simple equation for which we have to find the derivative with respect to time.

\frac{dS}{dt}=\pi*2d\frac{dD}{dt} Now let's look at the problem and see what we are given as far as information.

The rate at which the surface area changes is -3.8, and we are looking for \frac{dD}{dt}, the rate at which the diameter is changing, when the diameter is 13. Filling in:

-3.8=\pi(2)(13)\frac{dD}{dt} and solving for the rate at which the diameter is changing:

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What is 5x^2-7x-3=8 by solving using a graph???
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Hello!

Simplifying
5x2 + -7x + -3 = 8

Reorder the terms:
-3 + -7x + 5x2 = 8

Solving
-3 + -7x + 5x2 = 8

Solving for variable 'x'.

Reorder the terms:
-3 + -8 + -7x + 5x2 = 8 + -8

Combine like terms: -3 + -8 = -11
-11 + -7x + 5x2 = 8 + -8

Combine like terms: 8 + -8 = 0
-11 + -7x + 5x2 = 0

Begin completing the square. Divide all terms by
5 the coefficient of the squared term:

Divide each side by '5'.
-2.2 + -1.4x + x2 = 0

Move the constant term to the right:

Add '2.2' to each side of the equation.
-2.2 + -1.4x + 2.2 + x2 = 0 + 2.2

Reorder the terms:
-2.2 + 2.2 + -1.4x + x2 = 0 + 2.2

Combine like terms: -2.2 + 2.2 = 0.0
0.0 + -1.4x + x2 = 0 + 2.2
-1.4x + x2 = 0 + 2.2

Combine like terms: 0 + 2.2 = 2.2
-1.4x + x2 = 2.2

The x term is -1.4x. Take half its coefficient (-0.7).
Square it (0.49) and add it to both sides.

Add '0.49' to each side of the equation.
-1.4x + 0.49 + x2 = 2.2 + 0.49

Reorder the terms:
0.49 + -1.4x + x2 = 2.2 + 0.49

Combine like terms: 2.2 + 0.49 = 2.69
0.49 + -1.4x + x2 = 2.69

Factor a perfect square on the left side:
(x + -0.7)(x + -0.7) = 2.69

Calculate the square root of the right side: 1.640121947

Break this problem into two subproblems by setting
(x + -0.7) equal to 1.640121947 and -1.640121947.

Subproblem 1
x + -0.7 = 1.640121947

Simplifying
x + -0.7 = 1.640121947

Reorder the terms:
-0.7 + x = 1.640121947

Solving
-0.7 + x = 1.640121947

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.7' to each side of the equation.
-0.7 + 0.7 + x = 1.640121947 + 0.7

Combine like terms: -0.7 + 0.7 = 0.0
0.0 + x = 1.640121947 + 0.7
x = 1.640121947 + 0.7

Combine like terms: 1.640121947 + 0.7 = 2.340121947
x = 2.340121947

Simplifying
x = 2.340121947

Subproblem 2
x + -0.7 = -1.640121947

Simplifying
x + -0.7 = -1.640121947

Reorder the terms:
-0.7 + x = -1.640121947

Solving
-0.7 + x = -1.640121947

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.7' to each side of the equation.
-0.7 + 0.7 + x = -1.640121947 + 0.7

Combine like terms: -0.7 + 0.7 = 0.0
0.0 + x = -1.640121947 + 0.7
x = -1.640121947 + 0.7

Combine like terms: -1.640121947 + 0.7 = -0.940121947
x = -0.940121947

Simplifying
x = -0.940121947

Solution
The solution to the problem is based on the solutions
from the subproblems.
x = {2.340121947, -0.940121947}
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Answer:

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