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morpeh [17]
3 years ago
5

Both renewable and nonrenewable resources are used with our society. How do the uses of nonrenewable resources compared to the u

ses of renewable resources?
Chemistry
2 answers:
Marta_Voda [28]3 years ago
4 0

Answer:

Explanation:

The renewable resources are those which can be re-utilized again after once used. The non- renewable resources are those resources which cannot be utilized after a single used. The renewable resources are abundantly available in nature and their supply is not going to end for example water, forests, sunlight and wind. The renewable resources are limited in availability and if they become scarce their concentration cannot be maintained. For example, fossil fuels and inorganic minerals.

Thus the use of non-renewable resources should be done in sustainable way so that they remain available for future.

lukranit [14]3 years ago
3 0
Nonrenewable we only use them and renewable we can use them over and over.
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Drag each item to indicate whether it is related to Aristotle's or Ptolemy's model of the solar system, or to both. Some items m
Romashka-Z-Leto [24]

Answer:

<u>Aristotle's Model :</u>

geocentric

planets fixed on nested spheres

<u></u>

<u>Ptolemy's model:</u>

geocentric

planets fixed on epicycles

accurately predicted the positions of the planets

Explanation:

Let's begin by the fact both models are geocentric  and make a brief explanation of them:

<u></u>

<u>Aristotle's Model :</u>

Aristotle built his model based on observations and philosophical assumptions, not on measurements or calculations, then he mistakenly thought the Earth was the center of the universe.

So, according to this model, the universe was spherical and finite, with the Earth immobile at its center, composed of the four fundamental elements (made up of spherical layers): <em>ground, water, air and fire</em>; and the Sun along with the fixed planets in their respective concentric spheres (also called nested spheres) revolving around the Earth.

<u>Ptolemy's model:</u>

Ptolemy's model of the universe was also geocentric, placing the Earth motionless in the center of the known universe and was the accepted model for a long time during the Middle Ages.

In this sense, ccording to Ptolemy's model of the universe our planet remains stationary while the other planets, the Moon and the Sun describe complicated orbits around it (called epicycles).

However, this model predicted with an acceptable accuracy for that time the motion of the known planets, until Copernicus appeared with the revolutionary Heliocentric model.

5 0
3 years ago
How many moles of c6h12o6 are consumed if 6 moles of o2 are consumed
Mrac [35]
C₆H₁₂O₆, or glucose, is oxidized in the presence of oxygen to form carbon dioxide and water. The reaction equation for this is:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
Therefore, if 6 moles of oxygen are consumed, we can see from the equation that one mole of C₆H₁₂O₆ will be consumed.
3 0
3 years ago
Having studied the data for patterns and trends, you should now be able to draw
avanturin [10]

Answer:

The situation given here is imaginary such that the life of Rock has to be found using the half-life of the element lokium that has been found inside the rock.

Half-life of any material is the amount of time taken by that particular material to decay. Now the amount of lokium found in rock can show after how many half-lives this amount has been left out.

The time elapsed will be log (L) atoms X half-life.

Explanation:

3 0
2 years ago
What is the theoretical yield if 35.5g of Al reacts 39.0g of Cl2
atroni [7]

Answer : The correct answer for the Theoretical Yield is 48.93 g of product .

Theoretical yield : It is amount of product produced by limiting reagent . It is smallest product yield of product formed .

Following are the steps to find theoretical yield .

Step 1) : Write a balanced reaction between Al and Cl₂ .

2 Al + 3 Cl₂→ 2 AlCl₃

Step 2: To find amount of product (AlCl₃) formed by Al .

Following are the sub steps to calculate amount of AlCl₃ formed :

a) To calculate mole of Al :

Given : Mass of Al = 35.5 g

Mole can be calculate by following formula :

Mole = \frac{given mass (g)}{atomic mass \frac{g}{mol}}

Mole = \frac{35.5 g }{26.9 \frac{g}{mol}}

Mole = 1.32 mol

b) To find mole ratio of AlCl₃ : Al

Mole ratio is calculated from balanced reaction .

Mole of Al in balanced reaction = 2

Mole of AlCl₃ in balanced reaction = 2.

Hence mole ratio of AlC; l₃ : Al = 2:2

c) To find mole of AlCl₃ formed :

Mole of AlCl_3 = Mole of Al * Mole ratio

Mole of AlCl_3 = 1.32 mol of Al * \frac{2}{2}

Mole of AlCl₃ = 1.32 mol

d) To find mass of AlCl₃

Molar mass of AlCl₃ = 133.34 \frac{g}{mol}

Mass of AlCl3 can be calculated using mole formula as:

1.32 mol of AlCl_3 = \frac{ mass (g)}{133.34 \frac{g}{mol}}

Multiplying both side by 133.34 \frac{g}{mol}

1.32 mole  * 133.34\frac{g}{mol} = \frac{mass (g)}{133.34\frac{g}{mol}} *133.34  \frac{g}{mol}

Mass of AlCl₃ = 176.00 g

Hence mass of AlCl₃ produced by Al is 176.00 g

Step 3) To find mass of product (AlCl₃) formed by Cl₂ :

Same steps will be followed to calculate mass of AlCl₃

a) Find mole of Cl₂

Mole of Cl_2 = \frac{39.0 g}{70.9\frac{g}{mol}}

Mole of Cl₂ = 0.55 mol

b) Mole ratio of Cl₂ : AlCl₃

Mole of Cl₂ in balanced reaction = 3

Mole of AlCl₃ in balanced reaction = 2

Hence mole ratio of AlCl₃ : Cl₂ = 2 : 3

c) To find mole of AlCl₃

Mole of AlCl_3 = mole of Cl_2 * mole ratio

Mole of AlCl_3 = 0.55  mole  * \frac{2}{3}

Mole of AlCl3 = 0.367 mol

d) To find mass of AlCl₃ :

0.367 mol of AlCl_3 = \frac{mass (g) }{133.34 \frac{g}{mol}}

Multiplying both side by

133.34 \frac{g}{mol}

0.367 mol of AlCl_3 * 133.34 \frac{g}{mol}  = \frac{mass(g)}{133.34\frac{g}{mol}}   * 133.34 \frac{g}{mol}

Mass of AlCl₃ = 48.93 g

Hence mass of AlCl₃ produced by Cl₂ = 48.93 g

Step 4) To identify limiting reagent and theoretical yield :

Limiting reagent is the reactant which is totally consumed when the reaction is complete . It is identified as the reactant which produces least yield or theoretical yield of product .

The product AlCl₃ formed by Al = 176.00 g

The product AlCl₃ formed by Cl₂ = 48.93 g

Since Cl₂ is producing less amount of product hence it is limiting reagent and 48.93 g will be considered as Theoretical yield .

7 0
3 years ago
Read 2 more answers
If 0.0692 mol CaCl2 is dissolved in water to make a 0.810 M solution, what is the volume of the solution?
Natali5045456 [20]

Answer:

Just ask google for help

Explanation:

I always do it and get it right

8 0
3 years ago
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