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morpeh [17]
3 years ago
5

Both renewable and nonrenewable resources are used with our society. How do the uses of nonrenewable resources compared to the u

ses of renewable resources?
Chemistry
2 answers:
Marta_Voda [28]3 years ago
4 0

Answer:

Explanation:

The renewable resources are those which can be re-utilized again after once used. The non- renewable resources are those resources which cannot be utilized after a single used. The renewable resources are abundantly available in nature and their supply is not going to end for example water, forests, sunlight and wind. The renewable resources are limited in availability and if they become scarce their concentration cannot be maintained. For example, fossil fuels and inorganic minerals.

Thus the use of non-renewable resources should be done in sustainable way so that they remain available for future.

lukranit [14]3 years ago
3 0
Nonrenewable we only use them and renewable we can use them over and over.
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What Can You Tell About The Shape Of The Compound Made Of Magnesium & Nitrogen ?
earnstyle [38]
3. I am not sure what is meant by shape, it could be to do with structure. 


4. It is magnesium nitride, as adding nitrogen makes a nitride 
3 0
3 years ago
Which equation represents a transuranium​
Maksim231197 [3]

Answer:

1) Since you have not provided the equations to select the right one, I am going to explain you the relevant facts that are used to solve this question.

2) The transuranium elements are the chemiical elements with atomic number greater than that of the uranium.

The atomic number of uranium is 92. So, the transuranium elements are the elements with atomic number 93 or greater.

This are some of the transuranium elements:

Neptunio - 93

Plutonium - 94

Americium - 95

Curium - 96

Berkelium - 97

Californium - 98

Einstenium - 99

And so all the known elements (the last one is the 118).

3) In a nuclear reaction the total mass number ( shown as superscript to the left of the symbol) and total atomic number (shown as subscript to the left of the symbol) are conserved.

4) Beta decay is the release of a beta particle, which is an electron (considered massles and with charge - 1). So, the beta decay is represented with the symbol:

0

 β, which means 0 mass and charge - 1.

-1

5) This is, then, an example of a β decay equation for one transuranium element:

239              239            0

     Np    →         Pu   +      β

 93                94            -1

As you see 239 = 239 + 0 and 93 = 94 - 1, showing that the total mass number ( shown as superscript to the left of the symbol) and the total atomic number (shown as subscript to the left of the symbol) are conserved.

Explanation:

3 0
4 years ago
The atomic mass of sulfur is 32.1 amu, and the atomic mass of oxygen is 16.0 amu. To the nearest tenth of a percent, what is the
Zielflug [23.3K]

Answer:

\%\ Composition\ of\ sulfur=40.1\ \%

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given , Mass of sulfur= 32.1 amu

Mass of oxygen = 16.0 amu

Mass of sulfur trioxide SO_3 = 32.1 amu + 3*16.0 amu = 80.1 amu

\%\ Composition\ of\ sulfur=\frac{Mass_{sulfur}}{Mass_{SO_3}}\times 100

\%\ Composition\ of\ sulfur=\frac{32.1\ amu}{80.1\ amu}\times 100=40.1\ \%

6 0
3 years ago
Which type of scientist would most likely study how electricity could be
Nikolay [14]

Electrical engineers are the scientists that study the production of electricity more efficient.

<h3>Which type of scientist would study how electricity could be produced more efficiently?</h3>

Electrical engineers are the type of scientist that would most likely study how electricity could be produced more efficiently because they produced new technologies which are cost efficient as well as produce high amount of electricity.

So we can conclude that electrical engineers are the scientists that study the production of electricity more efficient.

Learn more about electricity here: brainly.com/question/776932

#SPJ1

6 0
2 years ago
The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 104 (?-m)-1. The electron concentration is kno
Julli [10]

Answer:

7.43 × 10²⁴ m⁻³

Explanation:

Data provided in the question:

Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹

Electron concentration, n = 2.9 × 10²² m⁻³

Electron mobility, \mu_n = 0.14 m²/V-s

Hole mobility, \mu_p= 0.023 m²/V-s

Now,

σ = nq\mu_n+pq\mu_p

or

σ = q(n\mu_n+p\mu_p)

here,

q is the charge on electron = 1.6 × 10⁻¹⁹ C

p is the hole density

thus,

2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 +  p × 0.023 )

or

1.75 × 10²³ = 0.406 × 10²² + 0.023p

or

17.094 × 10²² = 0.023p

or

p = 743.217 ×  10²²

or

p = 7.43 × 10²⁴ m⁻³

5 0
4 years ago
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