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qaws [65]
3 years ago
8

if a volume of air occupying 12.0Lat 20celsius is heated to a new temperature of 100 celsius,what would be the new volume

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

V₂ = 15.3

Explanation:

Given data:

Initial volume = 12.0 L

Initial temperature = 20°C

Final temperature =100°C

Final volume = ?

Solution:

First of all we will convert the temperature into kelvin.

20°C + 273 = 293 K

100°C + 273 = 373 K

Formula:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 12.0 L × 373 K / 293 k

V₂ = 4476 L.K /293 k

V₂ = 15.3

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

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Ann [662]

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

  • <em>mass of the sodium chloride, = 14.5 g</em>
  • <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>

<em />

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of  Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl -------------------  ?

= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g

Learn more here:brainly.com/question/8470145

8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
vazorg [7]

Answer:

See explanation

Explanation:

A double replacement reaction is a reaction where the atoms in the molecules replace each other to form two new molecules. However, if the products of the solution are soluble, then they could combine with the solution, and form a different set of products than expected.

Hope this helps!

3 0
3 years ago
A sample of gas at 301 Kelvin and 1.5 atmospheres has a density of 3.90 g/L. What is the molar mass of this gas? Show all of the
meriva
PV = nRTP is pressure, V is volume in L, n is number of moles, R is the gas constant,and T is temperature in K

(1.5 atm)(1 L) = (n)(.08206)(301K)

n = .06 moles in one liter

If there are 3.9 grams in .06 moles then

1/.06 x 3.9 = 64.2 grams per mol


4 0
3 years ago
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2 HCl + 1 Zn -&gt; 1 H2 + ZnCl2 what type of reaction is this
Salsk061 [2.6K]

Answer:

Single replacement reaction

Explanation:

3 0
3 years ago
Find out no. of moles present is 72 gm of water?
Alona [7]
72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O 
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2 years ago
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